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the area of a rectangleis 100 square inches. The perimeter of the rectangle is 40 inches. A second rectangle has the same area but a different perimeter. Is the secind rectangle a square? Explain why or why not.
The perimeter is 40 mm.
Assuming you meant area of 40 cm2, the rectangle would need to be 40 cm x 1 cm
The formula for the area (A) of a rectangle is A = length x width : Let w be the unknown side then 2000 = 50w : w = 2000 ÷ 50 = 40 feet Perimeter of a rectangle = 2(length + width) = 2(50 + 40) = 2 x 90 = 180 feet
The perimeter would be 40.
10
Length of rectangle is 18 units and its width is 2 units
2 x 18 2 x4
A rhombus can't have two different side lengths. They all must be the same. If the sides are 30-in, then the perimeter is 120-in. If they're 40-in, then the perimeter is 160-in.
Assuming that the measures given in the question refer to the lengths of the sides of the rectangle, the answer is 40 metres.
To find the perimeter of the rectangle you add up all the sides. There are two lengths and widths for every rectangle, so you know the length is 40 meters x 2 = 80 meters. Perimeter is the total length of all the sides so you just minus 120 from the two lengths which is 80. So the width is 40, divide 2 (2 widths) = 20 meters. Width = 20 meters OR if they're asking for widthS then it'll be 40 meters, but they're not.
the area of a rectangleis 100 square inches. The perimeter of the rectangle is 40 inches. A second rectangle has the same area but a different perimeter. Is the secind rectangle a square? Explain why or why not.
The perimeter is 40 mm.
Perimeter = 12 + 12 + 8 + 8 = 40.
Assuming you meant area of 40 cm2, the rectangle would need to be 40 cm x 1 cm
The perimeter is the total of all 4 sides of the rectangle, and a rectangle, by definition, has 2 sets of parallel sides. Perimeter = 2L + 2W (where L = length of ONE side, and W = width of ONE side). So, for example, if the perimeter is 40 cm, and the length is 15 cm, you figure out the width by subtraction and division. P = 2L + 2W 40 = 2(15) + 2W 40 = 30 + 2W 40-30 =30 + 2W - 30 10 = 2W 10/2 = 2W/2 5 = W So the width of the rectangle is 5 cm.
The formula for the area (A) of a rectangle is A = length x width : Let w be the unknown side then 2000 = 50w : w = 2000 ÷ 50 = 40 feet Perimeter of a rectangle = 2(length + width) = 2(50 + 40) = 2 x 90 = 180 feet