A rhombus can't have two different side lengths. They all must be the same.
If the sides are 30-in, then the perimeter is 120-in.
If they're 40-in, then the perimeter is 160-in.
2.5ins, 6ins and 6.5ins respectively.The perimeter of a 5-12-13 triangle would be 30 in.The shortest side is 5/30 = 1/6 of the perimeter, the middle side is 12/30 = 2/5 and the biggest is 13/30.So, for the triangle with perimeter 15 inches, the smallest side is 1/6*15 = 2.5 inches.The middle side is 2/5*15 = 6 inches and the biggest side is 13/30*15 = 6.5 inches.
How to solve: If you've got a square with perimeter of 120 cm, the first step is to determine the lengths of each side. Since it's a square, we have 4 sides of equal length. So divide 120 cm by 4. This gives you a side length of 30 cm. Area of a square is side length squared, so we have 30 x 30, which gives and area of 900 cm2 Short answer = 900 cm2
6
The perimeter is the total of all 4 sides of the rectangle, and a rectangle, by definition, has 2 sets of parallel sides. Perimeter = 2L + 2W (where L = length of ONE side, and W = width of ONE side). So, for example, if the perimeter is 40 cm, and the length is 15 cm, you figure out the width by subtraction and division. P = 2L + 2W 40 = 2(15) + 2W 40 = 30 + 2W 40-30 =30 + 2W - 30 10 = 2W 10/2 = 2W/2 5 = W So the width of the rectangle is 5 cm.
5,12,13
If a polygon with a perimeter of 30 centimeters has sides with length 6 cm/side, then it has 30 cm / 6 cm per side = 5 sides. So a regular pentagon with a side length of 6 cm has a perimeter of 30 centimeters.
if you have the length of one side - plus the perimeter... Divide the perimeter by 2, then subtract the known side - this leaves you with the unknown dimension. For example... Say you have a side length of 10, and a perimeter of 30. 30/2 = 15, subtract 10 from that - and you get the missing measurement of 5.
4*7.5 = a perimeter of 30 cm
the diagonals of a rhombus measure 16 cm and 30 cm.find its perimeter.
30
Each side S = square root ( 152 + 202 ) = 25The perimeter will then be 4 x S = 100
30 feet
With perimeter 10 and all sides equal fora rhombus, each side (base) is 10/4 = 2.5 inch Area = base times altitude = 2.5 x 12 = 30
The perimeter of a rectangle is not sufficient to determine its length.
The length of one side of the square is 7 1/2 meters. A square has 4 sides, so 30 divided by 4 is 7.5.
Suppose the length of each side is s metres.Then perimeter = 4*s = 120 metresso that s - 30 metres.And therefore, area = s2= 900 metres2.Suppose the length of each side is s metres.Then perimeter = 4*s = 120 metresso that s - 30 metres.And therefore, area = s2= 900 metres2.Suppose the length of each side is s metres.Then perimeter = 4*s = 120 metresso that s - 30 metres.And therefore, area = s2= 900 metres2.Suppose the length of each side is s metres.Then perimeter = 4*s = 120 metresso that s - 30 metres.And therefore, area = s2= 900 metres2.
if the perimeter is 66in and the length is 3 all u have to do is this 3+3= 6 66-6=60 60/2=30 your width of one side of the rectangle is 30in 3 ^ _______ | | | | | | 30{ | | }30 | | | | ------------ ^ 3