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Q: What is the perimeter of a rhombus with 1 side measuring 17?

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If each side of the square is 17 cm then its perimeter is 4*17 = 68 cm

Area = 289 sq cm so length of side = sqrt(289) = 17 cm Then perimeter = 4*side = 4*17 = 68 cm

2l + 2w = 82 in.

Exactly as in the question its perimeter is 17 units of measurement

A pentagon has 5 sides A regular pentagon has all sides equal → perimeter of regular pentagon with side 17 cm = 5 × 17 cm = 85 cm

Perimeter of the square: 17+17+17+17 = 68 cm

17X5=85 85"

Perimeter = 38+17+38+17 = 110 units of measurement

the old perimeter is 17 * 2 The old perimeter = 38

A triangle with side a: 26, side b: 26, and side c: 17 inches has an area of 208.86 square inches.

The perimeter of a 17-acre square lot is 0.65 miles (3,442.14 feet).

Perimeter of rectangle: 24+17+24+17 = 82 meters

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