All the sides of a rhombus are equal and perimeter of a rhombus is equal to four times the side.
Perimeter = 4 x 17 units = 68 units
To find the perimeter of a square, you multiply the length of one side by 4. If each side measures (2 \frac{5}{6}), first convert this to an improper fraction: (2 \frac{5}{6} = \frac{17}{6}). Then, the perimeter is (4 \times \frac{17}{6} = \frac{68}{6} = \frac{34}{3}). Thus, the perimeter of the square is ( \frac{34}{3} ) or approximately (11 \frac{1}{3}).
2l + 2w = 82 in.
Exactly as in the question its perimeter is 17 units of measurement
Perimeter of the square: 17+17+17+17 = 68 cm
The perimeter of a square is calculated by adding the lengths of all four sides. Since all sides of a square are equal, the formula for the perimeter is ( P = 4 \times \text{side length} ). For a square with sides of 17 cm, the perimeter is ( P = 4 \times 17 , \text{cm} = 68 , \text{cm} ). Therefore, the perimeter of the square is 68 cm.
If each side of the square is 17 cm then its perimeter is 4*17 = 68 cm
Area = 289 sq cm so length of side = sqrt(289) = 17 cm Then perimeter = 4*side = 4*17 = 68 cm
2l + 2w = 82 in.
A pentagon has 5 sides A regular pentagon has all sides equal → perimeter of regular pentagon with side 17 cm = 5 × 17 cm = 85 cm
To find the perimeter of a triangle, you simply add the lengths of all three sides together. In this case, the perimeter would be 15 cm + 17 cm + 10 cm = 42 cm. So, the perimeter of the triangle with sides measuring 15 cm, 17 cm, and 10 cm is 42 cm.
Exactly as in the question its perimeter is 17 units of measurement
Perimeter of the square: 17+17+17+17 = 68 cm
17X5=85 85"
the old perimeter is 17 * 2 The old perimeter = 38
Perimeter = 38+17+38+17 = 110 units of measurement
A triangle with side a: 26, side b: 26, and side c: 17 inches has an area of 208.86 square inches.
The perimeter of a 17-acre square lot is 0.65 miles (3,442.14 feet).