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Q: What is the perimeter of a rhombus with a side of 11 and an altitude of 8?

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Area = side^2 side = √121 = 11 ft Perimeter = 4 x side = 4 x 11 = 44 ft.

Area = side^2 side = √121 = 11 ft Perimeter = 4 x side = 4 x 11 = 44 ft.

66

If each side length is 2.75, the figure must be a square or a rhombus. The perimeter is 2.75*4=11.===========================Answer #2:There's no reason the figure must be a square, a rhombus, or anything else.All you can say is that the sides are all apparently the same length, but there'sno telling how many of them there are.Perimeter = (2.75) x (number of sides in the figure)

Semi-perimeter means half the perimeter. Calculate the perimeter, then divide that by 2 to get the semi-perimeter.

44 (4 sides x 11 = 44)

55''

each angle is 60 degrees. If you know trigonometry sin 60 = Altitude/length of side (from Pythagoras) A = 9.526 inch Or, from Pythagoras theorem 5.5 squared + Altitude squared = 11 squared Altitude = 9.526

The area of square is : 1936.0

perimeter is the sum of all side lengths. Since a 9 by 11 has 2 sides 9 inch and 2 sides 11 inch, perimeter is 9+9+11+11 = 40 inches

lol how many sides? perimeter divided by sides equals length per side. 44/4 =11 then again 44/11=4.. how many sides?

It would be 3-5-11 with internal angles of 19.7-28.1-132.2, and a perimeter of 23.

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