Semi-perimeter means half the perimeter. Calculate the perimeter, then divide that by 2 to get the semi-perimeter.
To calculate the area of a triangle with side lengths of 11cm, 8cm, and 7cm, we first need to determine the semi-perimeter of the triangle. The semi-perimeter (s) is calculated by adding all three sides together and dividing by 2, so s = (11 + 8 + 7) / 2 = 13 cm. Next, we can use Heron's formula to find the area of the triangle, which is given by the formula: Area = √[s(s-a)(s-b)(s-c)], where a, b, and c are the side lengths. Plugging in the values, we get Area = √[13(13-11)(13-8)(13-7)] = √[1325*6] = √780 ≈ 27.93 cm².
If triangle RST equals triangle MNO then RT = MO = 11 units. All the rest of the question - the lengths of RS and ST are irrelevant.
A pentagon, which is a 5-sided figure, might have sides that are 11 inches long. But there are an infinite number of other lengths possible. If we are talking about a regular pentagon with a perimeter of 55 inches, then yes, each side of that pentagon is 11 inches long.
If CB is the hypotenuse, then AB measures, √ (62 - 52) = √ 11 = 3.3166 (4dp) If AB is the hypotenuse then it measures, √ (62 + 52) = √ 61 = 7.8102 (4dp)
perimeter is the sum of all side lengths. Since a 9 by 11 has 2 sides 9 inch and 2 sides 11 inch, perimeter is 9+9+11+11 = 40 inches
A scalene triangle
yes
No, the measures 6 inches, 5 inches, and 11 inches cannot be the side lengths of a triangle. According to the triangle inequality theorem, the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 6 + 5 = 11, which is not greater than 11, thus failing the triangle inequality condition.
yes it is possible.
Yes, it is possible to construct a triangle with side lengths of 6 cm, 11 cm, and 13 cm. To determine this, we can use the triangle inequality theorem, which states that the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 6 + 11 > 13, 6 + 13 > 11, and 11 + 13 > 6, all hold true, confirming that these lengths can form a triangle.
11, 4, 8
No, you cannot construct a triangle with side lengths 2 yd, 9 yd, and 10 yd. This is because the sum of the lengths of the two shorter sides (2 yd + 9 yd = 11 yd) must be greater than the length of the longest side (10 yd) to satisfy the triangle inequality theorem. Since 11 yd is greater than 10 yd, these lengths do not form a triangle.
To determine if segments with lengths 9, 4, and 11 can form a triangle, we can use the triangle inequality theorem. This states that the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 9 + 4 = 13, which is greater than 11; 9 + 11 = 20, which is greater than 4; and 4 + 11 = 15, which is greater than 9. Since all conditions are satisfied, the segments can indeed form a triangle.
No because the sum of the its 2 smaller sides must be greater than its longest side.
Yes.
Well, darling, to find the area of a triangle with those side lengths, you can use Heron's formula. So, plug in those side lengths (a=8, b=11, c=15) into the formula, calculate the semi-perimeter, and then solve for the area. Voilà, you've got yourself the triangle's area.
Yes and it will be a scalene triangle