If triangle RST equals triangle MNO then RT = MO = 11 units. All the rest of the question - the lengths of RS and ST are irrelevant.
What is the area of the triangle 10cm ,8cm and 6cm
A pentagon, which is a 5-sided figure, might have sides that are 11 inches long. But there are an infinite number of other lengths possible. If we are talking about a regular pentagon with a perimeter of 55 inches, then yes, each side of that pentagon is 11 inches long.
If CB is the hypotenuse, then AB measures, √ (62 - 52) = √ 11 = 3.3166 (4dp) If AB is the hypotenuse then it measures, √ (62 + 52) = √ 61 = 7.8102 (4dp)
perimeter is the sum of all side lengths. Since a 9 by 11 has 2 sides 9 inch and 2 sides 11 inch, perimeter is 9+9+11+11 = 40 inches
A scalene triangle
yes
yes it is possible.
11, 4, 8
No because the sum of the its 2 smaller sides must be greater than its longest side.
Yes.
Yes and it will be a scalene triangle
It is a scalene triangle
Yes, because 11 + 15 > 21, 11 + 21 > 15, and 15 + 21 > 11
No it is not possible because the sum of the lengths of the two sides has to be greater than the length of the third side. 5 + 4 = 9 which is less than 11, so we can't form a triangle with these sides.
Yes that is possible. To check, you add the two shorter sides, and they should be longer than the longest side.
No. One of the sides is longer than the other two combined. If the side which is 29 is AB then the side connected to it at A will never be able to meet the side connected to it at B.