Let the sides be s:-
If: 0.5*s squared*sin(60 degrees) = 97.428
Then: s = square root of 97.428*2/sin(60 degrees) => 15.00001094
Perimeter: 3*15 = 45 cm
Using trigonometry the area of the isosceles triangle 60 square cm and its perimeter is 48 cm both rounded to the nearest integer
Area of a triangle = 1/2*base*height Use Pythagoras to find the height which is 7.794228634 inches Area = 1/2*9*7.794228634 = 35.07402885 square inches Answer: 35 square inches to the nearest square inch.
13.00
15.00
2,138.5 rounded to the nearest integer is 2,139
It is: 0.5*4*4*sin(60 degrees) = 7 square cm rounded to nearest integer
Area of equilateral triangle: 0.5*12*12*sin(60 degrees) = 187 square cm
Area of equilateral triangle: 0.5*8*8*sin(60 degrees) = 27.7 square inches rounded
Using the sine rule in trigonometry the perimeter of the triangle works out as 382cm rounded to the nearest integer
That depends on what is meant by length of AD but the 3 sides of an equilateral triangle are all equal in lengths.
Using trigonometry the area of the isosceles triangle 60 square cm and its perimeter is 48 cm both rounded to the nearest integer
5
Each side is: 16.65/3 = 5.55 cm Area is: 0.5*5.55*5.55*sin(60 degrees) = 13.34 square cm rounded
14.00
16.9
Area of a triangle = 1/2*base*height Use Pythagoras to find the height which is 7.794228634 inches Area = 1/2*9*7.794228634 = 35.07402885 square inches Answer: 35 square inches to the nearest square inch.
1.00