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What is the perimeter of an equilateral triangle whose area is the square root of 48 in square cm?
Wiki User
∙ 8y ago
Let its sides be x
If: 0.5*x^2*sin(60) = square root of 48
Then by making x the subject of the above equation it works out as 4
Therefore perimeter: 4+4+4 = 12 cm
Wiki User
∙ 8y ago
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