64 in.
Octagon has 8 side. Total perimeter is 208 mm, hence each side = 208/8 = 26 mm
If the permiter of a regular octagon is 8z-16, then the length of each side would be the perimeter / 8 or 2z-2
Each side is 56/8 (7).
perimeter of octagon is 128 cm= 8 * side side of the octagon=128/8=16 cm
8 (measure of each side) x 8 (total sides of an octagon) = 64cm
if there 8 sides on an octagon then 8 times 4 should give you your answer which is ....... 32
Octagon: 8 sides; each side 12 cm; 12 x 8 = 96 cm
If it's a regular octagon, the perimeter is 8 times the length of one side.
If each side is 1cm long then its perimeter is 8 times 1cm = 8 centimeters
Multiply side length by 8.
By using the definition of "perimeter": you need to add the lengths of all eight sides. If it is a REGULAR octagon, you multiply the length of any side by 8, since all sides have the same length.
It depends how big it is. But the rule is: Side length x 8 = Perimeter. For example, if one side was eleven centimeters long then the perimeter would be P= 11 x 8. It would be eighty-eight centimeters. Note: This rule only works for regular octagons. If you need to find the perimeter of an irregular octagon, then you have to measure each side and add up the measurements of each side.