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Period = 1/frequency = 1/250 = 0.004 = 4 milliseconds

Q: What is the period of the wave motion for a wave with a frequency of 0.25kHz?

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Period = reciprocal of ('1' divided by) frequency = 1/500 = 0.002 seconds = 2 milliseconds

Period = 1 / frequency

0.48 KHz = 480 HzPeriod = 1/frequency = 1/480 = 0.0020833 second (rounded) = 21/12 milliseconds

Wave frequency f, and period of wave T are inverses, related by fT=1.

frequency = (wave speed)/(wavelength) frequency = 1/(period)

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Period = reciprocal of frequency = 1 / (500) = 0.002 second

Period = reciprocal of ('1' divided by) frequency = 1/500 = 0.002 seconds = 2 milliseconds

Period = 1/Frequency = 0.00175 seconds (approx)Period = 1/Frequency = 0.00175 seconds (approx)Period = 1/Frequency = 0.00175 seconds (approx)Period = 1/Frequency = 0.00175 seconds (approx)

Period = 1 / frequency

If the period increases, the frequency decreases.The product of (frequency) times (period) is always ' 1 '.

0.48 KHz = 480 HzPeriod = 1/frequency = 1/480 = 0.0020833 second (rounded) = 21/12 milliseconds

Wave frequency f, and period of wave T are inverses, related by fT=1.

0.95 kHz = 950 Hz So period = 1/950 seconds = 0.001053 seconds (approx)

The frequency is the reciprocal of the period. If the period is doubled, the frequency will change by a factor of 1/2.

The frequency and period of a wave are inversely proportional. Therefore, as the frequency increases, the period decreases. frequency = 1/period period = 1/frequency

yes as, period time = 1/ frequency

Period = 1 / frequency