Period = 1/frequency = 1/250 = 0.004 = 4 milliseconds
Period = reciprocal of ('1' divided by) frequency = 1/500 = 0.002 seconds = 2 milliseconds
Period = 1 / frequency
0.48 KHz = 480 HzPeriod = 1/frequency = 1/480 = 0.0020833 second (rounded) = 21/12 milliseconds
Wave frequency f, and period of wave T are inverses, related by fT=1.
frequency = (wave speed)/(wavelength) frequency = 1/(period)
Period = reciprocal of frequency = 1 / (500) = 0.002 second
Period = reciprocal of ('1' divided by) frequency = 1/500 = 0.002 seconds = 2 milliseconds
Period = 1/Frequency = 0.00175 seconds (approx)Period = 1/Frequency = 0.00175 seconds (approx)Period = 1/Frequency = 0.00175 seconds (approx)Period = 1/Frequency = 0.00175 seconds (approx)
Period = 1 / frequency
If the period increases, the frequency decreases.The product of (frequency) times (period) is always ' 1 '.
0.48 KHz = 480 HzPeriod = 1/frequency = 1/480 = 0.0020833 second (rounded) = 21/12 milliseconds
Wave frequency f, and period of wave T are inverses, related by fT=1.
0.95 kHz = 950 Hz So period = 1/950 seconds = 0.001053 seconds (approx)
The frequency is the reciprocal of the period. If the period is doubled, the frequency will change by a factor of 1/2.
The frequency and period of a wave are inversely proportional. Therefore, as the frequency increases, the period decreases. frequency = 1/period period = 1/frequency
yes as, period time = 1/ frequency
Period = 1 / frequency