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0.48 KHz = 480 Hz

Period = 1/frequency = 1/480 = 0.0020833 second (rounded) = 21/12 milliseconds

Q: What is the period of the wave motion for a wave with a frequency of 0.48 kHz?

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.048

30, 048, 000, 000

three million one hundred and twenty thousand and forty-eight

Three million, one hundred twenty thousand, forty-eight.

You begin with 1.63 g of MgCl2•xH2O. You end up with 0.762 g MgCl2. That means you lost 1.63 - 0.762 = 0.87 g of H2O. 0.762 g MgCl2 / 95.21 g (molar mass) = .00800 mol MgCl2 0.87 g H2O / 18.02 g (molar mass) = .048 mol H2O x = mol solute / mol solvent x = .048 mol H2O / .00800 mol MgCl2 x = 6 MgCl2•6H2O

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1 petabyte = 1 048 576 gigabytes So, 1 048 576 gigabytes times sixteen is 16 777 216 gigabytes. Hope this helps.

3 048 000

1 048 576 kilobytes are in a gigabyte.

1 megabyte = 1 048 576 bytes