If: y = 2x
Then: y^2 = 4x^2
If: x^2 +y^2 -8x -y +5 = 0
Then: x^2 +4x^2 -8x -2x +5 = 0
Transposing terms: 5x^2 -10x +5 = 0
Dividing all terms by 5: x^2 -2x +1 = 0
Factorizing the above: (x-1)(x-1) = 0 meaning x = 1
By substitution into original equations point of contact is made at: (1, 2)
A point and most of the time meets, a polygon is a circle thing that meets at some point!
Suppose the circle meets QR at A, RP at B and PQ at C. PQ = PR (given) so PC + CQ = PB + BR. But PC and PB are tangents to the circle from point P, so PC = PB. Therefore CQ = BR Now CQ and AQ are tangents to the circle from point Q, so CQ = AQ and BR and AR are tangents to the circle from point R, so BR = AR Therefore AQ = AR, that is, A is the midpoint of QR.
Equations: y = x+4 and x^2 +y^2 -8x +4y = 30 It appears that the given line is a tangent line to the given circle and the point of contact works out as (-1, 3)
True
a tangent to the circle
It works out that the tangent line of y -3x -5 = 0 makes contact with the circle of x^2 + y^2 -2x +4y -5 = 0 at (-2, -1)
A point and most of the time meets, a polygon is a circle thing that meets at some point!
true
Suppose the circle meets QR at A, RP at B and PQ at C. PQ = PR (given) so PC + CQ = PB + BR. But PC and PB are tangents to the circle from point P, so PC = PB. Therefore CQ = BR Now CQ and AQ are tangents to the circle from point Q, so CQ = AQ and BR and AR are tangents to the circle from point R, so BR = AR Therefore AQ = AR, that is, A is the midpoint of QR.
tangant of circle intercepts it only on one point. In real the point where tangent meets the circle and intercepts it are same
Equations: y = x+4 and x^2 +y^2 -8x +4y = 30 It appears that the given line is a tangent line to the given circle and the point of contact works out as (-1, 3)
Definition: a tangent is a line that intersects a circle at exactly one point, the point of intersection is the point of contact or the point of tangency. a tangent is a line that intersects a circle at exactly one point, the point of intersection is the (point of contact) or the **point of tangency**.
True
a tangent to the circle
If: y = 5x and y = 3 -x Then: 5x = 3 -x => 5x +x = 3 => 6x = 3 => x = 1/2 By substitution point of contact is at: (1/2, 5/2)
The radius and the tangent are perpendicular at the point on the circle where they meet.
The tangent line. A secant line hits the circle in two places and forms a cord, but the tangent line only hits the circle in one point and is always perpendicular to the radius of the circle which exists at that point.