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If: y = 2x

Then: y^2 = 4x^2

If: x^2 +y^2 -8x -y +5 = 0

Then: x^2 +4x^2 -8x -2x +5 = 0

Transposing terms: 5x^2 -10x +5 = 0

Dividing all terms by 5: x^2 -2x +1 = 0

Factorizing the above: (x-1)(x-1) = 0 meaning x = 1

By substitution into original equations point of contact is made at: (1, 2)

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Q: What is the point of contact when the line y equals 2x meets the circle x2 plus y2 -8x -y plus 5 equals 0?
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