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If: y = 5x and y = 3 -x

Then: 5x = 3 -x => 5x +x = 3 => 6x = 3 => x = 1/2

By substitution point of contact is at: (1/2, 5/2)

Q: What is the point of contact when y equals 5x meets y equals 3 -x on the Cartesian plane showing work?

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Coodinate: (2, 5) Equation: y = 7x+13 Slope: 7 Perpendicular slope: -1/7 Perpendicular equation: 7y = -x+37 Both equations intersect at: (-1.08, 5.44) Perpendicular distance: square root of [(-1.08-2)^2+(5.44-5)^2] = 3.111 to 3 d.p.

A system for identifying points on a plane or in space by their coordinates is called a Cartesian coordinate system.In a plane (2-dimensional), the Cartesian coordinate system is determined by the two perpendicular directed lines Ox as x-axis, and Oy as y-axis (where the point of intersection O is the origin) and the given unit length.For any point P in the plane, let M and Nbe points on the x-axis and y-axis such that PM is parallel to y-axis and PN is parallel to x-axis. If OM = x and ON = y, then (x, y) are the coordinates of the point P in this Cartesian coordinate system.Normally, Ox and Oy are chosen so that an an anticlockwise rotation of one right angle takes the positive x-direction to the positive y-direction.In 3-dimensional space, the Cartesian coordinate system is determined by the three mutually perpendicular directed lines Ox as x-axis, and Oy as y-axis,and OZ as z-axis (where the point of intersection O is the origin).For any point P in a space, let L be the point where the plane through P, parallel to the plane containing the y-axis and z-axis, meets the x-axis. Alternatively, L is the point on the x-axis such that PL is perpendicular to the x-axis. Let M and N be points on the y-axis and z-axis. The points L, M, and N are in fact three of vertixes of the cuboid with three of its edges along the coordinate axes and with O and P as opposite vertixes. If OL = x and OM = y, and ON = z, then (x, y, z) are the coordinates of the point P in this Cartesian coordinate system.

ec would equal 6 because ac equals 12 and e meets in the middle of the parrallelogram (ehh im not gonna explain anymore just trust me. i got the answer right on my quiz and i looked up exactly what you asked)

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Related questions

It's the horizontal line on the Cartesian plane that meets the y-axis at the origin at 90 degrees.

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It is: (x-3)2+(y+5)2 = 13

Circle equation: x^2 +y^2 -8x +4y = 30 Tangent line equation: y = x+4 Centre of circle: (4, -2) Slope of radius: -1 Radius equation: y--2 = -1(x-4) => y = -x+2 Note that this proves that tangent of a circle is always at right angles to its radius

Points: (13, 19) and (23, 17) Midpoint: (18, 18) Slope: -1/5 Perpendicular slope: 5 Perpendicular equation: y-18 = 5(x-18) => y = 5x-72

It works out that the tangent line of y -3x -5 = 0 makes contact with the circle of x^2 + y^2 -2x +4y -5 = 0 at (-2, -1)

Coordinate: (11, 17)If: 3x+4y-63.5 = 0Then: 4y = -3x+63.5 => y = -3/4x+15.875Slope: -3/4Perpendicular slope: 4/3Perpendicular equation: y-17 = 4/3(x-11) => 3y = 4x+7Both equations intersect at: (6.5, 11)Perpendicular distance: square root of [(6.5-11)^2+(11-17)^2] = 7.5

If: 3y = 9x+18 then y = 3x+6 with a slope of 3 Perpendicular slope: -1/3 Perpendicular equation: y-29 = -1/3(x-19) => 3y = -x+106 Both equations intercept at: (8.8, 32.4) Perpendicular distance: square root of (8.8-19)^2+(32.4-29)^2 = 10.75 rounded

Yes and it is the horizontal x axis on the Cartesian plane that meets the vertical y axis at right angles at the point of origin which is at (0, 0)

Points: (13, 17) and (19, 23) Midpoint: (16, 20) Slope of required equation: 5/4 Its equation: 4y = 5x or as y = 1.25x Its distance from (0, 0) to (16, 20) = 4 times sq rt 41

Equation of line: 3x-7y+4 = 0 Base of triangle: 4/3 Height of triangle: 4/7 Area of triangle: 0.5*4/3*4*7 = 8/21

Contact angle is the angle that a drop of liquid makes as it meets the surface or interface of another phase, usually a solid