If: y = 5x and y = 3 -x
Then: 5x = 3 -x => 5x +x = 3 => 6x = 3 => x = 1/2
By substitution point of contact is at: (1/2, 5/2)
Coodinate: (2, 5) Equation: y = 7x+13 Slope: 7 Perpendicular slope: -1/7 Perpendicular equation: 7y = -x+37 Both equations intersect at: (-1.08, 5.44) Perpendicular distance: square root of [(-1.08-2)^2+(5.44-5)^2] = 3.111 to 3 d.p.
A system for identifying points on a plane or in space by their coordinates is called a Cartesian coordinate system.In a plane (2-dimensional), the Cartesian coordinate system is determined by the two perpendicular directed lines Ox as x-axis, and Oy as y-axis (where the point of intersection O is the origin) and the given unit length.For any point P in the plane, let M and Nbe points on the x-axis and y-axis such that PM is parallel to y-axis and PN is parallel to x-axis. If OM = x and ON = y, then (x, y) are the coordinates of the point P in this Cartesian coordinate system.Normally, Ox and Oy are chosen so that an an anticlockwise rotation of one right angle takes the positive x-direction to the positive y-direction.In 3-dimensional space, the Cartesian coordinate system is determined by the three mutually perpendicular directed lines Ox as x-axis, and Oy as y-axis,and OZ as z-axis (where the point of intersection O is the origin).For any point P in a space, let L be the point where the plane through P, parallel to the plane containing the y-axis and z-axis, meets the x-axis. Alternatively, L is the point on the x-axis such that PL is perpendicular to the x-axis. Let M and N be points on the y-axis and z-axis. The points L, M, and N are in fact three of vertixes of the cuboid with three of its edges along the coordinate axes and with O and P as opposite vertixes. If OL = x and OM = y, and ON = z, then (x, y, z) are the coordinates of the point P in this Cartesian coordinate system.
ec would equal 6 because ac equals 12 and e meets in the middle of the parrallelogram (ehh im not gonna explain anymore just trust me. i got the answer right on my quiz and i looked up exactly what you asked)
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It's the horizontal line on the Cartesian plane that meets the y-axis at the origin at 90 degrees.
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It is: (x-3)2+(y+5)2 = 13
Circle equation: x^2 +y^2 -8x +4y = 30 Tangent line equation: y = x+4 Centre of circle: (4, -2) Slope of radius: -1 Radius equation: y--2 = -1(x-4) => y = -x+2 Note that this proves that tangent of a circle is always at right angles to its radius
Points: (13, 19) and (23, 17) Midpoint: (18, 18) Slope: -1/5 Perpendicular slope: 5 Perpendicular equation: y-18 = 5(x-18) => y = 5x-72
It works out that the tangent line of y -3x -5 = 0 makes contact with the circle of x^2 + y^2 -2x +4y -5 = 0 at (-2, -1)
Yes and it is the horizontal x axis on the Cartesian plane that meets the vertical y axis at right angles at the point of origin which is at (0, 0)
Coordinate: (11, 17)If: 3x+4y-63.5 = 0Then: 4y = -3x+63.5 => y = -3/4x+15.875Slope: -3/4Perpendicular slope: 4/3Perpendicular equation: y-17 = 4/3(x-11) => 3y = 4x+7Both equations intersect at: (6.5, 11)Perpendicular distance: square root of [(6.5-11)^2+(11-17)^2] = 7.5
If: 3y = 9x+18 then y = 3x+6 with a slope of 3 Perpendicular slope: -1/3 Perpendicular equation: y-29 = -1/3(x-19) => 3y = -x+106 Both equations intercept at: (8.8, 32.4) Perpendicular distance: square root of (8.8-19)^2+(32.4-29)^2 = 10.75 rounded
Points: (13, 17) and (19, 23) Midpoint: (16, 20) Slope of required equation: 5/4 Its equation: 4y = 5x or as y = 1.25x Its distance from (0, 0) to (16, 20) = 4 times sq rt 41
Contact angle is the angle that a drop of liquid makes as it meets the surface or interface of another phase, usually a solid
The contact angle is the angle in which the liquid interface meets the solid surface. The contact angle should be as small as possible to have an effective penetrant material.