This question, as given, is meaningless. It does not specify the substance - oil, wine, air - whose cost is required.
20 liters is around 5.29 U.S. gallons ( VOLUME )
Volume of pacific ocean is 1.4*10^20
20 liters per km is about 0.117 mpg
20 liters per two dekaliters.
Neither is longer as both are measures of volume as opposed to length. Note: that 20 gallons > 40 liters.
50 cc tidal volume (awfully little!) x 12 breaths/minute is 600 cc per minute, or 0.6 l. 50 cc tidal volume x 20 breaths/minute = 1000 cc per minute, or 1 l.
Human lungs are 2 liters in volume by average. So... Average breath rate is 12 breaths per minute. In one minute the patient would take in 24 liters of air. You are supplying 2 liters of pure oxygen + 4.8 liters from air (20% of the 24 liters (Percent oxygen in dry air)) = 6.8 liters of Oxygen per minute. 6.8 liters oxygen / 24 liters intake = 28.3% Oxygen or you can look at the table given by the books at http://www.fpnotebook.com/ER/Procedure/LwFlwOxygn.htm Nasal Cannula, Flow 0 liters per minute: 21% (Room Air), Flow 2 liters per minute: 29% But I like the mathematical method. That's just me!
20 liters per 100 km = 14.1 miles per Imperial gallon.
H = 0.00308 meters.
Approximately, US units of capacity equal to 3.79 liters
would be:Amount : 3.79 gallons liquid US (gal in volume and capacity)Equals : 14.35 liters (l / volume and capacity)Fraction : 14 7/20 liters (l / volume and capacity)
Take example that we r providing 2L/min of oxygen to a ptHuman lungs are 2 liters in volume by average. So...Average breath rate is 12 breaths per minute.In one minute the patient would take in 24 liters of air. You are supplying 2 liters of pure oxygen + 4.8 liters from air (20% of the 24 liters (Percent oxygen in dry air)) = 6.8 liters of Oxygen per minute.6.8 liters oxygen / 24 liters intake = 28.3% Oxygen
The 20 foot by 40 foot cylindrical tank has a volume of 1005.7142857142849 cubic feet.