58 = 2 x 29. No prime power exists since there are no duplicate prime numbers in the prime factorization.
No. 7 is not a factor of 58. The prime factors of 58 are 2 and 29.
The prime factorization of 144 is 2^4 * 3^2. The prime factor is 2 and the exponent is 4.
Assume this problem deals with multiples of the numbers. The objective is vague, but I'm pretty sure of what is asked here.If we want to find the gcd of these terms, factor out each term and select the prime factor with the least exponent. Finally, evaluate the product of all prime factors. For instance:12 = 3 x 2²= 2² x 30 x 11044 = 11 x 2²= 2² x 30 x 112² has the least exponent for prime factor 2 of all these factorizations.30 has the least exponent for prime factor 3.110 has the least exponent for prime factor 11.The rest of other "invisible" prime factors, like 5 and 7, have the least exponent, which is 0!Therefore, the gcd is 2² = 4!
In a prime factorization, exponents are a form of shorthand.2 x 2 x 2 x 3 x 3 x 3 is the prime factorization of 216.That can be written as 23 x 33
The exponent indicates the number of times the base is used as a factor.
It is termed as a prime factor. 2 and 29 are the prime factors of 58
No. 7 is not a factor of 58. The prime factors of 58 are 2 and 29.
3,888 = 24 x 35
Highest prime factor in 58 is 29 and that in 26 is 13. But there is no highest common factor for 58 and 26.
The prime factorization of 144 is 2^4 * 3^2. The prime factor is 2 and the exponent is 4.
Assume this problem deals with multiples of the numbers. The objective is vague, but I'm pretty sure of what is asked here.If we want to find the gcd of these terms, factor out each term and select the prime factor with the least exponent. Finally, evaluate the product of all prime factors. For instance:12 = 3 x 2²= 2² x 30 x 11044 = 11 x 2²= 2² x 30 x 112² has the least exponent for prime factor 2 of all these factorizations.30 has the least exponent for prime factor 3.110 has the least exponent for prime factor 11.The rest of other "invisible" prime factors, like 5 and 7, have the least exponent, which is 0!Therefore, the gcd is 2² = 4!
To find the highest common factor you first need to break the numbers down into their prime factors. In this case 34 and 58 are broken down as follows: 34 = 2x17 58 = 2x29 The next step is to identify any common prime factors. In this case, the only common prime factor is a single 2. Therefore the highest common factor of 34 and 58 is 2.
Suppose you have a prime factor with an exponent of n. Then that prime factor can appear 0, 1, 2, ... , n times in a compound factor: that is, there are (n+1) different exponents that it can take.
There are no exponents needed. The prime factorization of 102 is: 2 x 3 x 17
58/77 is already in simplest form, since the greatest common factor of 58 and 77 is 1.The prime factorization of 58 is 2*29The prime factorization of 77 is 7*11The greatest common factor of 58 and 77 is 1.
58 is a composite number because it has factors other than 1 and itself. It is not a prime number.The 4 factors of 58 are 1, 2, 29, and 58.The factor pairs of 58 are 1 x 58 and 2 x 29.The proper factors of 58 are 1, 2, and 29 or,if the definition you are using excludes 1, they are 2 and 29.The prime factors of 58 are 2 and 29.The distinct prime factors (listing each prime factor only once) of 58 are also 2 and 29.The prime factorization of 58 is 2 x 29.NOTE: There cannot be common factors, a greatest common factor, or a least common multiple because "common" refers to factors or multiples that two or more numbers have in common. The prime factorization of 58 is 2x29.58/2 = 2929/29 = 1
The greatest common factor of the numbers 38 and 58 is 2.. 2 is the only common factor since 19 and 29 are both prime 2X19=38; 2X29=58