2 x 2 x 7 = 28
2 x 2 x 11 = 44
2 x 2 x 2 x 7 = 56
56 and 44
28 = 56
It is: 4
The factors of 56 are: 1 2 4 7 8 14 28 56 The prime factorization is: 2 x 2 x 2 x 7
The prime factorization of 56 is:7 x 23 = 56
To find the Least Common Multiple (LCM) of 98, 56, and 28, we first need to find the prime factorization of each number. The prime factorization of 98 is 2 * 7^2, the prime factorization of 56 is 2^3 * 7, and the prime factorization of 28 is 2^2 * 7. To find the LCM, we take the highest power of each prime factor that appears in any of the numbers. Therefore, the LCM of 98, 56, and 28 is 2^3 * 7^2, which equals 392.
28 x 56 = 4,000,000
44 = 2 * 2 * 11 = 22 * 1156 = 2 * 2 * 2 * 7 = 23 * 7
56 is 8*7
The prime factorization of 18 is 2 x 3 x 3. The prime factorization of 56 is 2 x 2 x 2 x7.
56 prime factorization 2*2*2*7 exponents: 23*7 * = multiply
56