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Q: What is the prime factors of 945?

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945 = 3x3x5x7

The factors of 945 are 1 3 5 7 9 15 21 27 35 45 63 105 135 189 315 945. The prime factors of 945 are 3, 5, and 7.

7

As a product of its prime factors: 3*3*3*5*7 = 945

945 = 33 x 5 x 7

For 945: 3, 5 and 7 For 441: 3 and 7

As a product of its prime factors: 3*3*3*5*7 = 945

315*3 = 945 does.

3 x 3 x 3 x 5 x 7 = 945

The GCF of 420, 735, and 945 is 105.The prime factorization of 420 is 2x2x3x5x7The prime factorization of 735 is 3x5x7x7The prime factorization of 945 is 3x3x3x5x7(1) List the prime factors of each number.(2) Multiply those factors all numbers in the set have in common. If there are no common prime factors, the GCF is 1. (Those factors are the ones in bold type.)As you can see the GCF is 3x5x7 or 105

To find the prime factors, you can start with any two factors of 945: 5 X 189 Keep factoring until all factors are prime: 5 X 3 X 63 5 X 3 X 3 X 21 5 X 3 X 3 X 3 X 7 Then, you can put the prime factors in order from smallest to largest: 3 X 3 X 3 X 5 X 7 The prime factors of 945 are 33, 5, and 7.

1 and 945

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