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Q: How do you sovle the prime factorization of 945?

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As a product of its prime factors: 3*3*3*5*7 = 945

945 Divide by three. 315,3 Divide by three. 105,3,3 Divide by three. 35,3,3,3 Divide by five. 7,5,3,3,3 Stop. 3 x 3 x 3 x 5 x 7 = 945

945 = 3x3x5x7

945 = 33 x 5 x 7

81 is not prime. Its prime factorization is 3x3x3x3.

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That's the prime factorization of 945.

As a product of its prime factors: 3*3*3*5*7 = 945

3 x 3 x 3 x 5 x 7 = 945

3 x 3 x 3 x 5 x 7 = 945

3 x 3 x 3 x 5 x 7 = 945 33 x 5 x 7 = 945

The GCF of 420, 735, and 945 is 105.The prime factorization of 420 is 2x2x3x5x7The prime factorization of 735 is 3x5x7x7The prime factorization of 945 is 3x3x3x5x7(1) List the prime factors of each number.(2) Multiply those factors all numbers in the set have in common. If there are no common prime factors, the GCF is 1. (Those factors are the ones in bold type.)As you can see the GCF is 3x5x7 or 105

945 Divide by three. 315,3 Divide by three. 105,3,3 Divide by three. 35,3,3,3 Divide by five. 7,5,3,3,3 Stop. 3 x 3 x 3 x 5 x 7 = 945

945 = 3x3x5x7

The prime factorization of 91 is 13 x 7 They are both prime so its a prime factorization

907 + 31 + 5 + 2 = 945

945 = 33 x 5 x 7

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