1 in 2
50%
1 in 2 children born will be male.
Nowadays it is approximately 0.5169
50% then 25%
50%
It is always 50/50.
To determine the probability of selecting a family with exactly 3 male children out of 4, we can use the binomial probability formula. The probability of having a male child is typically considered to be 0.5 (assuming an equal likelihood of male and female). The probability of exactly 3 males in 4 children is calculated as ( P(X = 3) = \binom{4}{3} (0.5)^3 (0.5)^1 = 4 \times 0.125 \times 0.5 = 0.25 ). Thus, the probability is 0.25 or 25%.
The probability of a boy (male) is equal to the probability of a girl (female) which equals 1/2. The king is a male. So, we need the probability of a male and a male which is 1/2 * 1/2 = 1/4.
The probability of a male passing on the rickets gene depends on the inheritance pattern of the gene in question. If the gene is X-linked, a male (XY) will pass the gene to all his daughters but none of his sons. In a case of autosomal inheritance, each child, regardless of sex, has a 50% chance of inheriting the gene from an affected male. Further specifics about the genetic background and family history would be needed for a precise probability.
The probability that mathematics will make a male pregnant is zero!
The probability of a colorblind child being born is 50%. This is because the male passes his Y chromosome to all his sons, and since he is colorblind, his sons will inherit the colorblind gene from him. The daughters will inherit their X chromosome from the mother and have a 50% chance of being carriers like her.
No probability. Neither parent has an "A" for the child to inherit to make an "AB".