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Any time there are two options, heads or tails when you flip a coin for example, the probability is 1/2, that the result will be either one option, or the other. The expected result when the coin lands is a 1/2 probability that it will be heads, and a 1/2 probability that it will be tails. What "1 out of 2 failing" means is that for every two students that take an exam, for example, one of them will fail. Of course, it also means, that 1/2 will pass.

Q: What is the probability of 1 out of 2 failing?

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If the probability of succeeding is 2%, then the probability of failing is 98%. The probability, then, of failing 75 times is 98%75, which is 22%.

The probability is 1/2.The probability is 1/2.The probability is 1/2.The probability is 1/2.

Assuming the alternator's failures are unrelated, the probability of both failing is the product of the individual probability, or 0.022, or 0.0004. The duration of the flight does not matter.

The probability is 1/2.

The probability is that the remaining two outcomes are 1 H and 1 T. The probability of that is 2/4 or 50%The probability is that the remaining two outcomes are 1 H and 1 T. The probability of that is 2/4 or 50%The probability is that the remaining two outcomes are 1 H and 1 T. The probability of that is 2/4 or 50%The probability is that the remaining two outcomes are 1 H and 1 T. The probability of that is 2/4 or 50%

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This question cannot be answered for two reasons.The questions states that "... the probability of each failing [is] 2 ...". That is not possible since probabilities can never be greater than 1.The question does not specify what even the probability is required for: the guidance system failing or not failing!

P(one failing) = 0.02P(one not failing) = 1-0.02 = 0.98P(whole string NOT failing) = 0.9820P(whole string failing) = 1-P(whole string NOT failing) = 0.3324

The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.

The probability is 1/2.

Let say the dice has n sides Let first search for the probability to roll a number less or equal to 2 Probability to roll a 1 = 1/n Probability to roll a 2 = 1/n Probability to roll a 1 OR a 2 = Probability to roll a 1 + Probability to roll a 2 = 1/n + 1/n = 2/n Probability to roll a number greater than 2 = 1 - (Probability to roll a 1 OR a 2) = 1 - 2/n = (n-2)/n If n = 6 then the result is (6-2)/6 = 4/6 = 2/3

Seems like the probability for a single shot is 0.6 So the probability of success with shot 1 is 0.6 and the probability of failing with the first and winning with the second is 0.4x0.6=0.24, same for the other way around, and the probability if winning both times is 0.6x0.6=0.36, and the probability of failing both times is 0.4x0.4=0.16, which is the same as (1-2x.24-.36) Multiply the probability by 100 to get percent.

The probability of getting zero tails is 1/2. The probability of getting zero tails twice in a row is 1/2 x 1/2 = 1/4. The probability of getting zero tails three times in a row is 1/2 x 1/2 x 1/2 = 1/8, etc... .

The probability of Tails on the first toss is 1/2.The probability of Tails on the second toss is 1/2.The probability of Tails on the third toss is 1/2.The probability of Tails on the fourth toss is 1/2.The probability of Tails on the fifth toss is 1/2.The probability of Tails on the sixth toss is 1/2.The probability of Tails on the seventh toss is 1/2.The probability of all of them is (0.5 x 0.5 x 0.5 x 0.5 x 0.5 x 0.5 x 0.5) = (0.5)7 = 0.0078125= 0.78125 %

Probability of drawing a heart: 1/4 Probability of drawing a club: 1/4 Probability of drawing a heart or a club: 1/4 + 1/4 = 2/4 = 1/2

The probability to get tails once is 1/2 (for a fair coin) The probability to get tails twice = the probability to get it once x the probability to get it a second time The probability to get tails 4 times in a row is (1/2)4=1/16 The probability to get tails n times in a row is (1/2)n=1/2n The same thing is also true for heads (same probability: 1/2 each time)

The probability is: 1/6 times 1/6 = 1/36

Assuming that the probability of having a baby girl is 1/2 and that of having a baby boy is 1/2, the probability of having 3 baby girls in a row is (1/2)(1/2)(1/2)=1/8.