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Any time there are two options, heads or tails when you flip a coin for example, the probability is 1/2, that the result will be either one option, or the other. The expected result when the coin lands is a 1/2 probability that it will be heads, and a 1/2 probability that it will be tails. What "1 out of 2 failing" means is that for every two students that take an exam, for example, one of them will fail. Of course, it also means, that 1/2 will pass.
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What is the probability of failing 75 times on a 2 percent chance of success?
If the probability of succeeding is 2%, then the probability of failing is 98%. The probability, then, of failing 75 times is 98%75, which is 22%.
What is probability of 1 even die and 1 odd when rolling 2 dice?
The probability is 1/2.The probability is 1/2.The probability is 1/2.The probability is 1/2.
The probability that a given alternator will fail on a 1-hour flight is 02 What is the probability that both will fail?
Assuming the alternator's failures are unrelated, the probability of both failing is the product of the individual probability, or 0.022, or 0.0004. The duration of the flight does not matter.
What is the probability that a 2 digit number is even?
The probability is 1/2.
What is the probability of obtaining exactly four tails in five flips of a coin given that at least three are tails?
The probability is that the remaining two outcomes are 1 H and 1 T. The probability of that is 2/4 or 50%The probability is that the remaining two outcomes are 1 H and 1 T. The probability of that is 2/4 or 50%The probability is that the remaining two outcomes are 1 H and 1 T. The probability of that is 2/4 or 50%The probability is that the remaining two outcomes are 1 H and 1 T. The probability of that is 2/4 or 50%
What is the probability of failing 75 times on a 2 percent chance of success?
If the probability of succeeding is 2%, then the probability of failing is 98%. The probability, then, of failing 75 times is 98%75, which is 22%.
What is the probability of a missile guidance system with 7 fail-safe components with the probability of each failing being 2 assume the variable is binomial?
This question cannot be answered for two reasons.The questions states that "... the probability of each failing [is] 2 ...". That is not possible since probabilities can never be greater than 1.The question does not specify what even the probability is required for: the guidance system failing or not failing!
What is probability of 1 even die and 1 odd when rolling 2 dice?
The probability is 1/2.The probability is 1/2.The probability is 1/2.The probability is 1/2.
20 Lights wired in series. One fails they all fail. Each light has .02 probability of failing in 3 years. Lights fail independently of one another. What is the probability that string fails in 3 yrs?
P(one failing) = 0.02P(one not failing) = 1-0.02 = 0.98P(whole string NOT failing) = 0.9820P(whole string failing) = 1-P(whole string NOT failing) = 0.3324
The probability that a given alternator will fail on a 1-hour flight is 02 What is the probability that both will fail?
Assuming the alternator's failures are unrelated, the probability of both failing is the product of the individual probability, or 0.022, or 0.0004. The duration of the flight does not matter.
What is the probability that a 2 digit number is odd?
The probability is 1/2.
What is the probability that a 2 digit number is even?
The probability is 1/2.
What is the probability that the a dice 2 is drawn if the two dice total is 5?
The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.
What is the probability of obtaining exactly four tails in five flips of a coin given that at least three are tails?
The probability is that the remaining two outcomes are 1 H and 1 T. The probability of that is 2/4 or 50%The probability is that the remaining two outcomes are 1 H and 1 T. The probability of that is 2/4 or 50%The probability is that the remaining two outcomes are 1 H and 1 T. The probability of that is 2/4 or 50%The probability is that the remaining two outcomes are 1 H and 1 T. The probability of that is 2/4 or 50%
What is the probablity of rolling a number greater than 2 on one roll of a die?
Let say the dice has n sides Let first search for the probability to roll a number less or equal to 2 Probability to roll a 1 = 1/n Probability to roll a 2 = 1/n Probability to roll a 1 OR a 2 = Probability to roll a 1 + Probability to roll a 2 = 1/n + 1/n = 2/n Probability to roll a number greater than 2 = 1 - (Probability to roll a 1 OR a 2) = 1 - 2/n = (n-2)/n If n = 6 then the result is (6-2)/6 = 4/6 = 2/3
What is the probability of getting a head or a tail when spinning 2 coins?
The "or" in the statement is addition; so even with one coin the probability of getting a head or a tail when spinning it is 1, and since the probability can never be greater than 1, the answer is 1. Correct. I suspect the questioner means something different. Probability of getting H & H = 1/2x1/2 = 1/4 Probability of getting H & T = 1/2 x 1/2 = 1/4 Probability of getting T & H = 1/2 x 1/2 = 1/4 Probability of getting T & T = 1/2 x 1/2 = 1/4 So probability of getting just 1 head = 1/4 +1/4 = 1/2 Probability of getting 2 heads = 1/4 So probability of getting 1 or 2 heads = 1/2 + 1/4 = 3/4 Probability of not getting a head = 1/4 Similarly for switching heads and tails.
If you want to knock a marble off the table with 60 percent success 30 out of 50 shots make it what is the probability of knocking a marble out if you take two shots?
Seems like the probability for a single shot is 0.6 So the probability of success with shot 1 is 0.6 and the probability of failing with the first and winning with the second is 0.4x0.6=0.24, same for the other way around, and the probability if winning both times is 0.6x0.6=0.36, and the probability of failing both times is 0.4x0.4=0.16, which is the same as (1-2x.24-.36) Multiply the probability by 100 to get percent.
