The "or" in the statement is addition; so even with one coin the probability of getting a head or a tail when spinning it is 1, and since the probability can never be greater than 1, the answer is 1.
Correct. I suspect the questioner means something different.
Probability of getting H & H = 1/2x1/2 = 1/4
Probability of getting H & T = 1/2 x 1/2 = 1/4
Probability of getting T & H = 1/2 x 1/2 = 1/4
Probability of getting T & T = 1/2 x 1/2 = 1/4
So probability of getting just 1 head = 1/4 +1/4 = 1/2
Probability of getting 2 heads = 1/4
So probability of getting 1 or 2 heads = 1/2 + 1/4 = 3/4
Probability of not getting a head = 1/4
Similarly for switching heads and tails.
Just one head = 2/4 = 1/2
It is 0.00540 approx.
50%
50/50
7/8
Just one head = 2/4 = 1/2
By tossing two coins the possible outcomes are:H & HH & TT & HT & TThus the probability of getting exactly 1 head is 2 out 4 or 50%. If the question was what is the probability of getting at least 1 head then the probability is 3 out of 4 or 75%
It is 0.00540 approx.
3/8 * * * * * That is the probability of getting EXACTLY 1H. The prob of getting one (or more) head is 7/8
is it 50% or 100% dang, i just confused myself. what if you toss 3 coins all at the same time... what's the probability of getting a head then, is it > 100% ? Doh!
one out of four
50%
1/8 or 12.5%
When we toss a coin getting head or tail have equal probability of 50% - that is, out of the two possible outcomes getting the specified one becomes 1/2 probability. When we toss three coins, the probability of getting all the coins showing tails is given by (1/2) * (1/2) * (1/2) equal to 1/8 or 12.5 % chance. Alikban
50/50
The probability of getting a head is 1/2 and if you toss it 4 times, the probability of 4 heads is (1/2)^4=1/16 since the tosses are independent events.
7/8