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It is 14/20 or 7/10.
10 possibilities, only three (7, 8 & 9) are greater than 6 so probability is 0.3 or 30%
Let P(A) = 1/10; P(A) = probability of selecting one people on a basketball team P(B) = 1/35; P(B) = probability of selecting one people on a football team P(C) = 1/10 = probability of selecting one people who plays in both teams P(D) = probability of selecting from either team. P(D) = P(A) + P(B) - P(C) P(D) = 1/10 + 1/35 - 1/10 P(D) = 1/35 or 0.0286
from 1-25 there are 25 numbers 1 3 5 7 9 11 13 15 17 19 21 23 25 = 13 numbers [2 4 6 8 10 12 14 16 18 20 22 24 = 12 numbers] so probability of selecting an odd number is 13 in 25 13:25
There are 4 numbers (7-10) which are greater than 6 → pr(>6) = 4/10 = 2/5
It is 0.4
There are 10 numbers {1, 2, ..., 10} The solution set contains {4, 5, ...,10} - 7 numbers in total → probability = number of successful tries/total number of tries = 7/10 = 0.7
It is 14/20 or 7/10.
10 possibilities, only three (7, 8 & 9) are greater than 6 so probability is 0.3 or 30%
Probability = 10 is a very serious mistake since the probability of any event can never be greater than 1: so a probability of 10 is obviously a big error.
If the only numbers to pick from are 1 through 8, how can you get a factor greater than 10?
25/50 gives the probability of selecting a blue marble
Let P(A) = 1/10; P(A) = probability of selecting one people on a basketball team P(B) = 1/35; P(B) = probability of selecting one people on a football team P(C) = 1/10 = probability of selecting one people who plays in both teams P(D) = probability of selecting from either team. P(D) = P(A) + P(B) - P(C) P(D) = 1/10 + 1/35 - 1/10 P(D) = 1/35 or 0.0286
from 1-25 there are 25 numbers 1 3 5 7 9 11 13 15 17 19 21 23 25 = 13 numbers [2 4 6 8 10 12 14 16 18 20 22 24 = 12 numbers] so probability of selecting an odd number is 13 in 25 13:25
There are 10 letters in the word "aspiration" and 5 of them are vowels. The probability of a randomly-selected letter being a vowel are 5/10 = 1/2 = 0.50.
3/10 or 0.3
There are 4 numbers (7-10) which are greater than 6 → pr(>6) = 4/10 = 2/5