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What is the probability of a 13-card hand containing one or more aces?
Wiki User
∙ 12y ago
The probability of a hand containing one or more aces is equal to 1 minus the probability of the hand not containing any aces. The probability for each card will be 48/52 multiplied by 47/51 multiplied by 46/50 and so on. This gives 0.30382
1 minus this is 0.696
Therefore the probability of a 13-card hand containing one or more aces is 0.696
Wiki User
∙ 12y ago
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In a poker hand consisting of 5 cards find the probability of holding 3 aces?
Approximately 2%
A poker hand five cards is drawn from an ordinary deck of 52 cards find the probability of the first four cards are the four aces?
4/52 x 3/51 x 2/50 x 1/49 About 0.00039%
How is probability related to genetics?
Probability and genetics go hand in hand. Mendel in his charts showed the probability of dominant and recessive genes being passed on to offspring. The desired trait could be cultivated knowing the probability of inheritance.
The probability of drawing somethingout of a bag?
If you reach into the bag, grasp, and withdraw your hand, the probability of pulling something out is about 100%.
What is the probability of having a perfect euchre hand?
next to impossible
In a poker hand consisting of 5 cards find the probability of holding 3 aces?
Approximately 2%
What is the probability of getting exactly three aces in a five-card poker hand dealt from an ordinary 52 card deck?
The probability of getting 3 aces in the order AAABB is; P(AAABB) = (4/52)∙(3/51)∙(2/50)∙(48/49)∙(47/48) = 0.0001736... There are 5C3 = 5!/(3!∙(5-3)!) = 10 different ways in which the aces can come out. So the probability of getting exactly three aces in a five card poker hand dealt from a 52 card deck is, P(3A) ~ 10∙(0.0001736) ~ 0.001736 ~ 0.1736%
What is the probability that a random selected poker hand contains exactly 3 aces given that it contains at least 2 aces?
I will assume that you mean a five card poker hand. We can label the cards C1, C2, C3, C4, and C5. We are basically told already that C1 and C2 are both aces. So we have to find the probability that exactly one of C3, C4, and C5 is an ace. Knowing that the first two cards in our hand are both aces means that there are only 50 cards left in the deck. The probability that C3 is an ace and that C4 and C5 are both not aces is (2/50)(48/49)(47/48)=0.03836734694. The same probability also applies to each of C4 and C5, considered independently of each other. Therefore, our final probability is 3* 0.03836734694=0.1151020408
What are chances of 4 aces being in a hand of 9 cards?
The probability of 4 aces being in a hand of 9 cards is: 9C4 ∙ (4/52)∙(3/51)∙(2/50)∙(1/49)∙(48/48)∙(47/47)∙∙∙(44/44) = 0.0004654... ≈ 0.0465% where 9C4 = 9!/[(9-3)!∙3!] = 126
What hand did Wild Bill Hickock hold when he died?
Aces over Eights; Full Hosue Wild Bill was holding a Full House, Aces and Eights. As a point of trivia, this is now referred to as the Dead Man's Hand. the hand was two pair, aces and eights
When you play poker cards game and you have straight Aces in your hand what that mean?
suited aces
What is the dead man's hand?
It is called the Deadman's Hand. Aces and 8s
What is a dead man's hand in casino?
Aces and eights
What is Dead mans hand in casino?
Aces and eights
What was wild bill Hickok famous for?
the hand: aces and eights, the dead man's hand
What are 'freerolls' in the game of poker?
A freeroll in the game of poker is a situation in which a player cannot win the hand and cannot lose the hand. An example of a freeroll hand is when a person has 2 aces and other person has 2 aces.
What is a dead man is hand?
The exact makeup of a Dead Man's Hand has varied over the years; it is currently black aces and eights. The fifth card is disputed. See link for more.
