The answer depends on how many blue and non-blue marbles there are, whether the choice is random and how many marbles are chosen. There is no information provided on any of these.
100%
it depends how many blue marbles there are and how many marbles total.
1/3 or 33%
cant answer this question without more information....probability requires a ratio.
We will assume that the bag contains 11 marbles (this is not a trick question!), so 4 are blue and 7 are not blue, so the probability of a color other than blue is 7/11.
The probability of choosing a blue marble is 5 in 15 or 1 in 3. The probability of then choosing a green marble is 5 in 14. (One is missing) Multiply the two probabilities and you get 5 in 42.(P = 0.1190... about 12%).
if there is a jar containing 5 red marbles 6green and 4 blue what is the probability off not chossing a blue marble
It can not be determined with the data provided.
100%
it depends how many blue marbles there are and how many marbles total.
This is the same as the probability of choosing either a red of a blue marble. There are 5+4 out of 15 ways of doing this. The probability is therefore 9/15 = 3/5.
1/3 or 33%
cant answer this question without more information....probability requires a ratio.
5:16
We will assume that the bag contains 11 marbles (this is not a trick question!), so 4 are blue and 7 are not blue, so the probability of a color other than blue is 7/11.
If one marble is chosen at random, the probability is 6/(4+6+5) = 6/15 = 2/5
The probability of choosing a green marble from this jar would be 6/15. You get this answer by adding up the sum of all the marbles.