It can not be determined with the data provided.
The probability of choosing a blue marble is 5 in 15 or 1 in 3. The probability of then choosing a green marble is 5 in 14. (One is missing) Multiply the two probabilities and you get 5 in 42.(P = 0.1190... about 12%).
This is the same as the probability of choosing either a red of a blue marble. There are 5+4 out of 15 ways of doing this. The probability is therefore 9/15 = 3/5.
If one marble is chosen at random, the probability is 6/(4+6+5) = 6/15 = 2/5
There are 16 marbles total and 7 green ones, so the probability is 7/16.
None, if all the marbles that you have are yellow!
if there is a jar containing 5 red marbles 6green and 4 blue what is the probability off not chossing a blue marble
The probability of choosing a blue marble is 5 in 15 or 1 in 3. The probability of then choosing a green marble is 5 in 14. (One is missing) Multiply the two probabilities and you get 5 in 42.(P = 0.1190... about 12%).
100%
it depends how many blue marbles there are and how many marbles total.
This is the same as the probability of choosing either a red of a blue marble. There are 5+4 out of 15 ways of doing this. The probability is therefore 9/15 = 3/5.
1/3 or 33%
cant answer this question without more information....probability requires a ratio.
5:16
The answer depends on how many blue and non-blue marbles there are, whether the choice is random and how many marbles are chosen. There is no information provided on any of these.
We will assume that the bag contains 11 marbles (this is not a trick question!), so 4 are blue and 7 are not blue, so the probability of a color other than blue is 7/11.
If one marble is chosen at random, the probability is 6/(4+6+5) = 6/15 = 2/5
The probability of choosing a green marble from this jar would be 6/15. You get this answer by adding up the sum of all the marbles.