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What is the probability of drawing a J or 2 or 6 from a deck of 52 cards using 3 chances?
Wiki User
∙ 13y ago
Chance of 2, 6, or J on the first draw is (4/52+4/52+4/52) = 12/52 = 3/13 = 23.1%
Chance of 2, 6, or J on the second draw is (4/51+4/51+4/51) = 12/51, as long as the first draw did not produce the correct card. (1-3/13)*12/51 = 10*12/13*51 = 18.1%
Chance of 2, 6, or J on the third draw is (4/50+4/50+4/50) = 12/50 = 6/25, as long as the first two draws did not produce the correct card (58.8%)*.24 = 14.1%
Total probability = 55.3%.
Wiki User
∙ 13y ago
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What is the probability of drawing an ace of spades on the first draw and a four of spades on the second draw using sampling without replacement.... how do you go about doing this problem?
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What is the probability of drawing an Ace or a Jack from a deck of 52 cards?
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What is the probability of drawing an ace of spades on the first draw and a four of spades on the second draw using sampling without replacement.... how do you go about doing this problem?
There are 52 cards in the deck.The probability of drawing the ace of spades on the first draw is 1/52 .Since you don't put the first card back, there are then 51 cards in the deck.The probability of drawing the 4 of spades on the second draw is 1/51 .The probability of both occuring is (1/52) x (1/51) = 1/2,652 = 0.037707 % (rounded)
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What is the probability of picking an ace and a king from a pack of playing cards?
The absolute probability is even, given one draw. However, statistically, the chance of drawing an ace and a king as two cards at random is 1: 81.25Chance of drawing first card is either an ace or a king is 8: 52 (1 in 6.5).Now the remaining other card (ace or king) is 4 in 51 (1 in 12.5)*In Blackjack, the drawing of any face card or 10 improves the odds of a natural blackjack using only one deck to 1: 20.8 but the show used holds more than one deck.
What is the probability of drawing an Ace or a Jack from a deck of 52 cards?
approx 15 %Reason: There are 2 cards in each suit of 13 that are either an Ace or a Jack.So there is a 2 out of 13 (or 8 out of 52) chance, which is 15.38% chance.IN FRACTION AND USING PERMUTATIONS AND COMBINATIONStotal number of cases : 52C1favorable cases : in cards there are 4 aces and 4 jacks, therefore 4+4 = 8P (of drawing an ace or a jack) = 8/52= 2/13odds against this question is : 2/(13-2)= 2/11 [ANS.]
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Assuming that you are using a full deck of playing cards, excluding Jokers, there would be four 3s in a deck of fifty-two total cards, making your chances of drawing a 3 the first time 1:13. However, to draw two 3s in a row in a true random scenario, we start with the condition that you have already drawn your first 3 (the 1:13 chance). Going from here, we would then have another 1:13 chance of drawing a 3, so we simply multiply the two ratios to arrive at a probably of 1:169.
Would an ordinary deck of 52 cards 26 red and 26 black 3 cards are drawn without replacement Using a tree diagram find the probability that all the cards drawn are black?
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From an ordinary deck of 52 cards 26 red and 26 black 3 cards are drawn without replacement Using a tree diagram find the probability that all the cards drawn are black?
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