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What is the probability of getting 3 red balls from an urn in 3 picks with replacement if the urn contains 5 red 3 blue and 2 green?
Wiki User
∙ 9y ago
1/8 = 0.125 = 12.5 %
The urn has 5 + 3 + 2 = 10 balls of which 5 are red.
→ Pr(first red) = 5/10 = 1/2
As the picked ball is replaced, the second and third reds have the same probability (1/2).
→ Pr(three reds) = 1/2 x 1/2 x 1/2 = 1/8
Wiki User
∙ 9y ago
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If A box contains three black balls and four gold balls Two balls are randomly drawn in succession from the box If there is no replacement what is the probability that both balls are black?
(3/7)*(2/7)=(6/49) You have a 6 out of 49 probability.
If an urn contains 6 yellow balls 3 red balls and 5 blue balls If 2 balls are drawn without replacement what is the probability of drawing 2 yellow balls?
The probability is (6/14)*(5/13) = 30/182 = 0.1648 approx.
What is the probability of choosing 3 red balls and 2 black balls out of a bag which contains 5 red balls 2 green balls and 4 black balls?
If you draw enough balls, without replacement, the probability is 1.The answer depends onhow many balls are drawn, andwhether or not they are replaced.Unfortunately, your question gives no information on these matters.
What is the probability of getting 3 red balls from an urn in 3 picks without replacement if the urn contains 5 red 3 blue?
The probability the first ball will be red is 5/8. The probability that the first and second balls will be red is 5/8 x 4/7. The probability that the first, second, and third balls will be red is 5/8 x 4/7 x 3/6, or overall 60/336 (about 17.86%).
If you draw 5 balls with replacement from an urn containing white balls and black balls is the probability of getting 3 white balls always higher than if you draw the balls without replacement?
The probability of getting 3 white balls in a draw of 5 balls with replacement from an urn containing white balls and black balls is always greater than the same test without replacement, because the number of white balls decreases when you draw a white ball and do not replace it. The ratio of white to black with replacement is constant, and is always less than one, assuming there is at least one black ball. The ratio of white to black without replacement decreases each turn, and is still less than one, and is less than the previous ratio, unless the question asked about 2 white balls or less.
A box contains 75 balls numbered from 1 to 75. If 12 balls are drawn with replacement what is the probability that at least two of them have the same number?
It is 0.6050
If A box contains three black balls and four gold balls Two balls are randomly drawn in succession from the box If there is no replacement what is the probability that both balls are black?
(3/7)*(2/7)=(6/49) You have a 6 out of 49 probability.
If an urn contains 6 yellow balls 3 red balls and 5 blue balls If 2 balls are drawn without replacement what is the probability of drawing 2 yellow balls?
The probability is (6/14)*(5/13) = 30/182 = 0.1648 approx.
What is the probability of choosing 3 red balls and 2 black balls out of a bag which contains 5 red balls 2 green balls and 4 black balls?
If you draw enough balls, without replacement, the probability is 1.The answer depends onhow many balls are drawn, andwhether or not they are replaced.Unfortunately, your question gives no information on these matters.
A box contains 7 red balls and 11 black balls two balls are taken out one after the other without replacement what is the probability that both balls are black?
11/18 x 10/17 = .359
What is the probability of getting 3 red balls from an urn in 3 picks without replacement if the urn contains 5 red 3 blue?
The probability the first ball will be red is 5/8. The probability that the first and second balls will be red is 5/8 x 4/7. The probability that the first, second, and third balls will be red is 5/8 x 4/7 x 3/6, or overall 60/336 (about 17.86%).
If you draw 5 balls with replacement from an urn containing white balls and black balls is the probability of getting 3 white balls always higher than if you draw the balls without replacement?
The probability of getting 3 white balls in a draw of 5 balls with replacement from an urn containing white balls and black balls is always greater than the same test without replacement, because the number of white balls decreases when you draw a white ball and do not replace it. The ratio of white to black with replacement is constant, and is always less than one, assuming there is at least one black ball. The ratio of white to black without replacement decreases each turn, and is still less than one, and is less than the previous ratio, unless the question asked about 2 white balls or less.
8 identical balls are placed at random in three bags. what is the probability that the first bag will contain 3 balls?
The probability that it contains exactly 3 balls is 6/45 = 0.133... recurring.
An Urn contains 5 white and 7 black balls five balls drawn at randoma Find the distribution function of the probability distribution of no of white balls?
with replacement: binominal distribution f(k;n,p) = f(0;5,5/12) without replacement: hypergeometric distribution f(k;N,m,n) = f(0;12,5,5)
When jar contains 6 blue balls 8 red balls and 6 yellow balls 2 balls selected without replacement.what is probability that first ball is red and second ball is blue?
If the balls are selected at random, then the probability is 12/95.
When an urn contains 12 red balls 153 blue balls 2 black balls 47 white balls and no green balls What is the probability you do not draw any ball at all?
2
A box contains four balls two red and two yellow balls we extract two balswhat is the probability of extracting two red balls?
It is 1/6.
