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Q: What is the probability of getting two 1's when two number cubes are rolled?

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4/12

If the number cubes are standard dice cubes, the odds of rolling 3 ones is 1 in 216.

With two fair cubes, the probability is 1/6.

The experiment is not defined! The probability of the event described, when 9 or more number cubes are rolled, is 0.

The probability is 21/36 = 7/12

impossible

1

Pr(7) = 1/36 Pr(11) = 2/36 = 1/18

The probability is 5/6.

I am not sure but I think 3/36

yes

The probability is 0.

The probability that any number will come up on one cube is 1/6. 1/6*1/6=1/36 the probability is 1/36

The first roll doesn't matter for probability, it just sets the number to be rolled by the other two. So: P(rolling the same number three times) = P(rolling a particular number)2 = (1/6)2 = 1/36

The probability is 0.277... (repeating).

The probability is 0.

If they are standard cubes - with numbers from 1 to 6 - the probability is 0.

A sum that is a factor of 6 has a greater probability.to my dick

On a normal cube, the probability is 0. If there are more than 1 cubes, the answer depends on how many are being rolled for each sum.

It is 1/6.

On a roll of two dice, the chance of rolling a 3 (one and two) is 2 in 36, or 1 in 18 when reduced.

Assuming that these number cubes are ordinary dice (number are 1-6) and that both dice are balanced (equal chances for each side to turn up), then it's 1/36. There are 36 different possibilites for the upturned faces when a pair of dice is rolled, one of which is "4 and 4".

First of all it is probability second of all the answer is 1/6+1/6 which is 2/12 which simplified is 1/6

50%

36