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Q: What is the probability of getting a sum of 5 when two number cubes are rolled?

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The probability is 5/6.

Assuming that these number cubes are ordinary dice (number are 1-6) and that both dice are balanced (equal chances for each side to turn up), then it's 1/36. There are 36 different possibilites for the upturned faces when a pair of dice is rolled, one of which is "4 and 4".

On a roll of two dice, the chance of rolling a 3 (one and two) is 2 in 36, or 1 in 18 when reduced.

There are a total of 36 outcomes. from 1,1; 1,2; .... to 6,5:6,6. For these to total '7' We have 1,6 ; 2,5 '; 3,4 ; 4,3 ; 5,2 ; & 6,1. There are six outcomes. So probability of a total of 7 ; P(total 7) = 6/36 = 1/6

Because 3/6 of the sides on a number cube have even numbers, the probability of rolling even on one number cube is 1/2(equivalent of 3/6). But since you're rolling twice, you multiply the probability of one by itself (therefore rolling 2 number cubes). So: 1/2x1/2=1/4 The probability of rolling an even number when a number cube is rolled twice is 1/4, 25%, or 1 out of 4.

Related questions

The probability is 1/36.

If the number cubes are standard dice cubes, the odds of rolling 3 ones is 1 in 216.

The experiment is not defined! The probability of the event described, when 9 or more number cubes are rolled, is 0.

The probability is 21/36 = 7/12

Pr(7) = 1/36 Pr(11) = 2/36 = 1/18

impossible

1

The probability is 5/6.

I am not sure but I think 3/36

yes

The probability is 0.

The probability that any number will come up on one cube is 1/6. 1/6*1/6=1/36 the probability is 1/36

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