The probability is 1.
At any point in time it is raining somewhere on earth.
It is 0.731 approx.
If the probability that it will rain is 0.25, then the probability that it is sunny is 0.75. The probability of it being sunny for five days, then is 0.755, or about 0.2373.
It depends upon how you are picking these numbers. Let's say you are rolling two dice. The probability of rolling 2 fours is 1 in 36. The probability of exactly 1 five is 10 in 36, while the probability of at least 1 five is 11 in 36. The probability of exactly 1 six is 10 in 36, while the probability of at least 1 six is 11 in 36. The probability of at least 1 five or 1 six is 19 in 36. The probability of exactly 1 five or six is 15 in 36. So no matter how you look at it, with dice rolling, the probability of 1 five or 1 six is bigger than the probability of 2 fours. However, if you are picking numbers from a hat, then the probabilities are different.
The probability that you will toss five heads in six coin tosses given that at least one is a head is the same as the probability of tossing four heads in five coin tosses1. There are 32 permutations of five coins. Five of them have four heads2. This is a probability of 5 in 32, or 0.15625. ----------------------------------------------------------------------------------- 1Simplify the problem. It asked about five heads but said that at least one was a head. That is redundant, and can be ignored. 2This problem was solved by simple inspection. If there are four heads in five coins, this means that there is one tail in five coins. That fact simplifies the calculation to five permutations exactly.
I suppose you mean, at least one of those numbers. Just calculate the probability of NOT getting any of those, and take the complement. The probability of not getting a one nor a five on a single die is 4/6 or 2/3. For two dice, the probability is 2/3 x 2/3 = 4/9. So, the probability of getting at least a one or a five with two dice is 1 - 4/9 = 5/9.I suppose you mean, at least one of those numbers. Just calculate the probability of NOT getting any of those, and take the complement. The probability of not getting a one nor a five on a single die is 4/6 or 2/3. For two dice, the probability is 2/3 x 2/3 = 4/9. So, the probability of getting at least a one or a five with two dice is 1 - 4/9 = 5/9.I suppose you mean, at least one of those numbers. Just calculate the probability of NOT getting any of those, and take the complement. The probability of not getting a one nor a five on a single die is 4/6 or 2/3. For two dice, the probability is 2/3 x 2/3 = 4/9. So, the probability of getting at least a one or a five with two dice is 1 - 4/9 = 5/9.I suppose you mean, at least one of those numbers. Just calculate the probability of NOT getting any of those, and take the complement. The probability of not getting a one nor a five on a single die is 4/6 or 2/3. For two dice, the probability is 2/3 x 2/3 = 4/9. So, the probability of getting at least a one or a five with two dice is 1 - 4/9 = 5/9.
The probability is 7:12... There are five months with less than 31 days, so the probability of selecting a month with exactly 31 days is 7 out of 12.
1/32
The probability that all will be graduates will be 5/20 x 4/19 x 3/18. This equals 0.0087719, or 0.877% The probability of at least one being a graduate is 1 minus the probability of none being graduates. That's 1-(15/20 x 14/19 x 13/18) = 1 - 0.39912280701754385964912280701754 = 0.600877 =60% Thus the probability of having at least one graduate is 60%
If five cards are drawn from a deck of cards without replacement, what is the probability that at least one of the cards is a heart?
The probability that the birthdays of five persons chosen at random will fall in twelve different calender months is zero. You would need at least twelve persons to have a non zero probability.
the probability is 0.03125 or 3.123%
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