this formula is all based down to Pythagoras' Theory. 5x^-2y^10 over 2x^-1(-3x^-3y^-1)^-2
1/6Because:There is a 4 in 9 chance of picking a red ball the first time and 3 in 8 chance of picking a red ball the second time. The chance of picking two reds as the first two balls is 4/9 x 3/8 or 12/72 or 1/6
Total number of fruit in the bag = 9 + 5 + 3 =17Number of Kiwi = 3Probability of picking a kiwi out of the bag =3/17
P(7)= 1/30
It is 1/7.
It is 1/13.
That depends. Picking a red ball is 4/9 Picking a green ball is 3/9 = 1/3 Picking a yellow ball is 2/9. Picking a ball is 9/9 or 1 because you'll always take one.
The probability of a black ball in bag 1 is 4/12 = 1/3. If you add 3 black balls to bag 2, it will contain 5 black balls out of 15: the probability of a black ball being 3/15 = 1/3.
11/19 is the probability 11 over 19 if you cant read it
1/6Because:There is a 4 in 9 chance of picking a red ball the first time and 3 in 8 chance of picking a red ball the second time. The chance of picking two reds as the first two balls is 4/9 x 3/8 or 12/72 or 1/6
The probability is 1/b.
1/13
there are 4 1's or aces in a pack of 52 cards. Probability of picking an ace=4/52=1/13
Probability is simple. Probability means the number of favorable outcomes over the total amount of outcomes.For example, if I had 15 marbles in a bag. 10 are yellow, and 5 are red. The probability of picking a yellow marble is 10/15, which simplifies to 2/3.
Total number of fruit in the bag = 9 + 5 + 3 =17Number of Kiwi = 3Probability of picking a kiwi out of the bag =3/17
The probability of picking a distinct set of 3 numbers from 20 is1/[20!/(3!)(17!)]= 1/1140The probability of only picking 3 from 20 is1/20
The probability of picking a black ace in one random draw from a normal pack of playing cards is 1/26.
Yes, it certainly can if there is only one possible outcome. For instance, the probability of drawing a red ball from a bag containing nothing but red balls is equal to one.