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It is 1 - pr(no 5 nor 6 in 120 rolls)

= 1 - (2/3)120

= 1 - 1.113*1057

which is so close to 1 as to make no difference.

It is 0.99...98887 which starts off with a string of 56 nines.

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Q: What is the probability of rolling a die 120 times and getting 5 or 6?
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