The probability that you roll a multiple of 3 (3 and 6) in a fair die is: P(3 or 6) = 2/6
=1/3 = 0.333... ≈ 33.3%.
The probability that you roll a multiple of 5 (5) is: P(5) = 1/6.
The probability that you roll a multiple of 3 or 5 is: P(3 or 6 or 5) = 2/6 + 1/6 = 1/2 = 0.50 = 50%
1/6
and the question is ... ?
Since there is only one even prime, 2, the probability of rolling a 2 with one die is 1 in 6.
"The probability of getting a prime number in a die is 4/6" Actually there are 3 prime numbers on a die. 2, 3, and 5 are all prime numbers. So this tells you that you have 3 chances it will be a prime number and 3 chances it will not be a prime number. So the probability of getting a prime number on a die would be 3/6 or 1/2.
total numbers taht can be occure=1,2,3,4,5,6 prime number taht can occure in a roll= 2, 3,5 total sample space= n=6 total faverable cases= m=3 P(prime number)=m/n=3/6=1/2 probability of rolling a prime number is 1/2
The probability of rolling a seven with one roll of a standard number cube is zero.
The probability of rolling a 5 on a roll of a single number cube is 1/6 (0.1666) as there is only one number 5 on a total of 6 sides on the cube.
(1/2)*(2/6) = 1/6
100% or 100/100
The probability is 0.
1/6
The probability is 0.The probability is 0.The probability is 0.The probability is 0.
What is the probability of rolling an even with one roll of a numbers cube.
1/2
what is the probability of P(4or6) as a fraction, decimal and a percent
On a single roll it is 2/3.
A 1/6 chance.