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"The probability of getting a Prime number in a die is 4/6"

Actually there are 3 prime numbers on a die. 2, 3, and 5 are all prime numbers. So this tells you that you have 3 chances it will be a prime number and 3 chances it will not be a prime number. So the probability of getting a prime number on a die would be 3/6 or 1/2.

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Q: If you roll a die what is the probability of rolling a prime number?

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1/6

Since there is only one even prime, 2, the probability of rolling a 2 with one die is 1 in 6.

total numbers taht can be occure=1,2,3,4,5,6 prime number taht can occure in a roll= 2, 3,5 total sample space= n=6 total faverable cases= m=3 P(prime number)=m/n=3/6=1/2 probability of rolling a prime number is 1/2

and the question is ... ?

On a standard die, 2:1 in favour. This would be correct if 1 and 2 are accepted as prime numbers, which is allowed by some mathematicians and theories though not by all. ---- Having worked it out myself, I believe there is actually an even probability: Prime numbers: * 2 * 3 * 5 Not-prime numbers: * 1 * 4 * 6

Related questions

1/6

3/6

5 out of 12

The probability is 5/12.

The probability is 1 out of two. The primes you can roll are 2,3, and 5.

Since there is only one even prime, 2, the probability of rolling a 2 with one die is 1 in 6.

1 out of 2 if the die is six-sided.

The probability of rolling a seven with one roll of a standard number cube is zero.

1 in 6, or 0.17.

First you need to work out the probability of rolling a prime number. The prime numbers on a die are 2, 3 and 5. Thus the probability of rolling a prime number is 3/6 which can be simplified to 1/2. The probability of rolling a number greater than 1 is 5/6. The probability of rolling one on one dice and one on the other is therefore 1/2 x 5/6 = 5/12. There are two possible ways round these options could come though. You might get the number greater than one on the first roll, and the prime on the second. Thus we need to multiply the probability by 2, which gives us the final answer of 5/6.

Assuming that "to" should actually be "two", Since the outcome on each die is independent, Pr(Roll a prime when rolling two dice) = Pr(Roll a prime on a die)2 = (1/2)2 = 1/4

It is 1 (a certainty) if you roll it often enough. For a single roll of a fair die, the probability is 1/6.

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