The probability of tossing a 1 or 2 on a six sided die is 2 in 6, or 1 in 3.
If the "number cube" you are referring to is what we normally call a die (one of a pair of dice), the chances of tossing an 8 are nothing since the cube has only 6 sides and is numbered 1 to 6. If a "number cube" is something else, perhaps someone else can answer the question.
The probability of tossing an odd number (assumed on a die) is 3 in 6 or 1 in 2. The probability of tossing a tail (assumed on a coin) is 1 in 2. Since these are unrelated events, and the question said "and", simply multiply the probabilities to get 1 in 4.
-3/12
1/2 * 1/2 = 1/4 1/2= probability of landing an even number 1/2 = probability of landing a heads
There are 36 possibilities when rolling two six sided die. 15 of them result in a prime number (2,3,5,7,11) So the probability is 15 in 36 or a 5 in 12 chance.
On a regular number cube, it is 1/6.
If a standard number cube or die is rolled, the probability that a 4 does not land face up is five out of six, or (six minus one) out of six.
The probability of tossing a die and getting three 6's in a row is (1/6)3, or about 0.004630.
The probability of a head is 1/2. The probability of an odd number is 1/2. 1/2 x 1/2 = 1/4 or 0.25
Each time you toss the die the probability of rolling an even number is 3 out of 6 or 1/2. So, the probability of tossing three consecutive even numbers is (1/2)3 = 1/8 = 0.125, which is one chance in eight.
The probability of rolling a prime number on a standard 6-sided die is 3 in 6, or 0.5.The sample space is [1 2 3 4 5 6] and the result space is [2 3 5]. 3 divided by 6 is 0.5.