5/12
Consider the possibile outcome of two rolls of a die (where order matters):
(1,1)
(1,2)
(1,3)
.
.
.
(4,6)
(5,6)
(6,6)
There are 6*6=36 possible outcomes. Of these, the following would achieve the result desired:
(1,2)
(1,3)
(1,4)
(1,5)
(1,6)
(2,3)
(2,4)
(2,5)
(2,6)
.
.
.
(5,6)
For the first die equal to 1, there are 5 successful results. For the first die equal to 2, there are 4 successful results....For the first die equal to 5, there is 1 successful result. The total number of successful outcomes=5+4+3+2+1.
So the probability that the desired outcome is obtained=(5+4+3+2+1)/36=15/36=5/12.
The probability is 1, if the dice are rolled often enough.
if you multiply the number of rolls you did you will get the answer
1/6
If they are normal dice, the probability is 0.
The answer depends on how many dice are rolled. With 12 or more dice, the answer is 0.The answer depends on how many dice are rolled. With 12 or more dice, the answer is 0.The answer depends on how many dice are rolled. With 12 or more dice, the answer is 0.The answer depends on how many dice are rolled. With 12 or more dice, the answer is 0.
The probability of any one number on a die being rolled is 1/6 or 16.67%.
If two six sided fair dice are rolled, the sum of the result of both dice that has the lowest probability to come up is 2 and 12. P(2) = 1/36. P(12) = 1/36.
It is 1/6.
The are 36 permutations of two dice. Of these, 6 permutations have the two dice with the same number, specifically 1+1, 2+2, 3+3, 4+4, 5+5, and 6+6. The probability, then, that two dice rolled will not have the same number is 30 in 36, or 5 in 6, or about 0.8333.
The probability is 1, if the dice are rolled often enough.
If you rolled 2 fair dice, the probability of having a sum of 6 is 5 over 36
one in sixsame for any number