If she is a 41% shooter she will probably score a goal 41 times out of a hundred, but she will probably miss the other 59 times out of a hundred. So the probability that she will miss is 59 out of 100 = 59% = 0.59
Use the definitions given in the text to find both the odds for and the odds against the following event.
Flipping 4 fair coins and getting4 tails.
the odds of getting 4 tails are
You want the probability of miss and miss and miss which is .67 * .67 * .67 = 0.301.
We'll if they are 89% it's pretty high
There is a 10 percent chance that you are gonna throw a 1.
The probability of four out of six shots is the probability of four successes, times the probability of two failures, times the number of permutations of successes and failures: P(four out of six free throws) = 15 * (2/5)4 * (3/5)2 = (15 * 16 * 9) / (625 * 25) = 432 / 3125
should be 1/6 chance for one. So 1/192 .5 percent
You want the probability of miss and miss and miss which is .67 * .67 * .67 = 0.301.
We'll if they are 89% it's pretty high
The probability the shooter makes both shots is .7 * .7 = .49, and the probability of making neither is .3 * .3 = .09. So the probability of making exactly 1 out of 2 is 1 - .49 - .9 = .42, or 42 percent.
There is a 58% chance they are going to miss.
In Division 1, Markus Howard from Marquette and Fletcher Magee from Wofford both have 100% free throw shooting
With a single throw of a normal die, the probability is 0.With a single throw of a normal die, the probability is 0.With a single throw of a normal die, the probability is 0.With a single throw of a normal die, the probability is 0.
Ben Wallace
yes
There is a 10 percent chance that you are gonna throw a 1.
The probability of four out of six shots is the probability of four successes, times the probability of two failures, times the number of permutations of successes and failures: P(four out of six free throws) = 15 * (2/5)4 * (3/5)2 = (15 * 16 * 9) / (625 * 25) = 432 / 3125
No, not that I ever heard of. It maybe if you are talking to the free throw shooter.
should be 1/6 chance for one. So 1/192 .5 percent