The probability is 0. One card cannot be a club and a spade!
Probability not a club = 1 - probability it is a club = 1 - 13/52 = 1 - 1/4 = 3/4.
It is 3/4.
Red card- 1/2 CLUB-1/4
It is 10/52 = 5/26.
One quarter of the pack are CLUB cards. Three quarters of the pack are NOT CLUB cards. So the chance (probability) of picking a CLUB card is 1 out of 4 = 0.25 The chance (probability) of picking a NOT CLUB card is 3 out of 4 = 0.75 Adding the various probabilities the answer must always be 1.0, which is true here. If the probability of something happening is 1.0, that means the probability is "certainty". It is bound to happen.
The probability is 22/52 = 11/26.
In an ordinary 52 card deck, there are 4 three's, and 13 clubs, one of which is the 3 of clubs, so there are 16 cards that are a three or a club. The probability of drawing a three or a club is 16 out of 52, or 4 out or 13, or 0.308.
"Pick A Club Card" is uncertain, in the context of the question. In all probability (no pun intended) the probability of picking a club from a random draw from a standard 52 card deck is 13 in 52, or 1 in 4, or 0.25.If the question means something else, please restate the question, giving more details.
In a standard deck of 52 cards - the probability of drawing any single card of two suits is 1:2 or 50%.
4/13
30.8% There are 13 club cards + 3 additional jacks (from diamonds, hearts and spades) for a total of 16 cards out of 52 Simplifying that the probability is 4 out of 13 or 30.8%