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What is the probability that a leap year selected at random will contain you 53 Sundays II 53 Thursdays?
Wiki User
∙ 11y ago
A Leap year has 366 days. in which you have 52 weeks and 2 days.
the 2 days may be
sun,Mon
mon,Tue
tue,wed
wed,THu,
thu,Fri
FRi,SAT
sat,sun
so you have 7 options among which 2 u can choose..
so the answer is 2/7 for having 53 Sundays. The probability of having 53 Thursdays is also 2/7.
The probability of having either 53 Sundays or 53 Thursdays is 4/7.
Wiki User
∙ 11y ago
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What is probability that a leap years selected at random will contain 53 Sundays?
probability = 2/7 to be exact, 28/97 (about 28.87%)
What is the probability that a leap year selected at random would contain 53 days Option a) 17 b) 27 c) 112 d) 14?
None of them. The probability of an event cannot be greater than one. Besides, every leap year will have 366 days, not 53!
What is the probability of not getting a king from a deck of 52 cards?
The probability that a standard deck of 52 cards does not contain a king is 0.
A sample of 4 iPods is selected from a shipment of 20 iPods there are 5 defective iPods in the shipment what is the probablity that the sample does not contain any defective iPods?
i dont get it? --- The probability that the first iPod you select is not defective is 16/20. If you selected a non-defective iPod the first time, there are now 15 non-defective iPods out of 19 remaining. So, the odds that the second you selected is non-defective is 15/19. By similar reasoning, the probability that the third is non-defective (given that the first two weren't defective) is 14/18, and for the fourth iPod, it is 13/17. So the probability that none of the four iPods you selected are defective is: (16/20)*(15/19)*(14/18)*(13/17)=364/969, or approximately 37.6%
What is probability of picture card in 52 cards?
A normal deck of 52 playing cards will ALWAYS contain picture cards, so the probability is 1.
What is probability that a leap years selected at random will contain 53 Sundays?
probability = 2/7 to be exact, 28/97 (about 28.87%)
What is the probability that a leap year selected at random would contain 53 days Option a) 17 b) 27 c) 112 d) 14?
None of them. The probability of an event cannot be greater than one. Besides, every leap year will have 366 days, not 53!
What is probability of getting a 3 in a deck of cards?
For an ordinary deck of cards, the probability is 1. All decks of playing cards contain 3s.For an ordinary deck of cards, the probability is 1. All decks of playing cards contain 3s.For an ordinary deck of cards, the probability is 1. All decks of playing cards contain 3s.For an ordinary deck of cards, the probability is 1. All decks of playing cards contain 3s.
What is the probability that a month will contain 31 days?
It is 7/12.
Jntuk 2009 may ptsp solved question paper?
1. a) A box of 30 diodes is known to contain five defective ones. If two diodes are selected at random without replacement, what is the probability that atleast one of these diodes is defective
What is the probability of not getting a king from a deck of 52 cards?
The probability that a standard deck of 52 cards does not contain a king is 0.
A sample of 4 iPods is selected from a shipment of 20 iPods there are 5 defective iPods in the shipment what is the probablity that the sample does not contain any defective iPods?
i dont get it? --- The probability that the first iPod you select is not defective is 16/20. If you selected a non-defective iPod the first time, there are now 15 non-defective iPods out of 19 remaining. So, the odds that the second you selected is non-defective is 15/19. By similar reasoning, the probability that the third is non-defective (given that the first two weren't defective) is 14/18, and for the fourth iPod, it is 13/17. So the probability that none of the four iPods you selected are defective is: (16/20)*(15/19)*(14/18)*(13/17)=364/969, or approximately 37.6%
What is the chance that a leap year selected at random will contain 53 Saturdays?
Since you are selecting only among leap years, either the first or the second day of the year would have to be a Saturday, so you have two chances out of seven (a probability of 2/7) that there are 53 saturdays.
What is probability of picture card in 52 cards?
A normal deck of 52 playing cards will ALWAYS contain picture cards, so the probability is 1.
The probability that a number selected from random between 100 and 999 both inclusive will not contatin the digit 7?
For me I think it is conceptually easier to think about the probability that the number will contain the digit seven (and the probability that it does not contain the digit 7 is simply one minus the probability that it does). P(number will contain 7) = P(number is in the seven hundreds) + P(number is not in seven hundreds)*[P(number is in the X hundred seventies)+P(number is not in the X hundred seventies)*P(number ends in seven)] So essentially I am considering all of the numbers in the range that start with seven (i.e., are in the seven hundreds), then all of the numbers in the range that aren't in the seven hundreds but have a 7 in the tens place (i.e., the 170s, 270s, etc., and finally all the numbers that don't have a 7 in the hundred or tens place, but that end in 7). Plugging the numbers into my formula above, I get (100/900)+(800/900)*((10/100)+(90/100)(1/10)) = 7/25 is probability that the number does contain a 7, and 1-(7/25)=18/25 is probability that it does not.
Acereal company says that 10 percent of all their boxes of cereals contain a prize You buy two boxes of cereal Find the probability that both boxes contain a prize?
The probability of a prize in the first box = 1/10.The probability of a prize in the second box = 1/10.The probability of prizes in both boxes = (1/10) x (1/10) = 1/100 = 1%
What is the probability that a month will contain 28 days?
It is 1. Every month contains 28 days.
