5/7
The composite numbers on an ordinary cube are 4 and 6 so the probability of rolling a composite is 2/6 = 1/3
25 33 50
It is 1/3.
72 is divisible by 6. (72 / 6 = 12) Hence 6 is a composite number of 72.
4 and 8 are the composite factors of 8. 4, 6 and 12 are the composite factors of 12.
There are 36 possible outcomes when two dice are rolled. The composite outcomes and the number of corresponding events are: 4 - 3 6 - 5 8 - 5 9 - 4 10 - 3 12 - 1 So there are 21 outcomes out of 36 where the result is a composite. So probability of a composite = 21/36 = 7/12 = 0.58333 or 58.333... %
The probability of rolling a composite number on a 6 sided die, numbered 1, 2, 3, 4, 5, and 6, is 1 in 3. There are two composite numbers on the die, 4 and 6. The others are prime, 2, 3, and 5, or unity, 1, so there are 2 possible outcomes in an possible result set of 6, hence the probability is 2 in 6, or 1 in 3.
All composite numbers have more than 2 factors. The factors of 12 are 1, 2, 3, 4, 6, and 12, and this proves that 12 is a composite number.
Yes. For example, 12 / 6 = 2.
The composite numbers are 4 and 6; that is 2/6 of the numbers available. Therefore the odds on rolling such a number are "two out of 6" = 1/3 = 33.333%The 3 in that answer is recurring.Since the total of all probabilities which might occur in one event is 1.0 or 1 or 100%, it follows that the probability of not throwing a composite number is 4/6 = 2/3 = 66.66666666666666(recurring)%
66>> 6+6=12
12 is not a prime number because it is a whole number that can be divided equally by 1, 2, 3, 4, 6, 12. So 12 is a composite number.