It is 1/(12^3) = 1/1728.
The probability of getting heads on a single coin flip is 0.5. To find the probability of getting heads four times in a row, you multiply the probability of getting heads for each flip: (0.5 \times 0.5 \times 0.5 \times 0.5 = 0.5^4 = 0.0625). Thus, the probability of flipping heads four times in a row is 6.25%.
1:4 i think
The probability is 1/4
Anyone can flip a coin four times so I say 100 percent probability. On the other maybe you should ask the odds of the results from four flips.
6.25%
The probability of flipping a fair coin four times and getting four heads is 1 in 16, or 0.0625. That is simply the probability of one head (0.5) raised to the power of 4.
four out of seven times
The probability of drawing four aces in a draw of four cards from a deck of 52 cards is 3 in 812175. (4 in 52) times (3 in 51) times (2 in 50) times (1 in 49)
To calculate the probability of getting at least four heads when flipping a coin six times, we can use the binomial probability formula. The total number of outcomes for six flips is (2^6 = 64). The probabilities for getting exactly four, five, and six heads can be calculated using the binomial formula, and their sum gives the total probability of getting at least four heads. This results in a probability of approximately 0.65625, or 65.625%.
The probability of four out of six shots is the probability of four successes, times the probability of two failures, times the number of permutations of successes and failures: P(four out of six free throws) = 15 * (2/5)4 * (3/5)2 = (15 * 16 * 9) / (625 * 25) = 432 / 3125
25:75
It is 0.6875