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To find P( at least 1 head in 7 tosses) we can find P( no heads) and subtract that

from one. Alternatively, we need to find P ( 1 head) + P ( 2 heads )+...+ P(7 heads)

Since P of no heads is P( all tails) this is (1/2)7 =.0078125 ( 1/128 as a fraction)

Now 1-(1/128)=127/128 or .9921875

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Q: What is the probability that at least 1 head appears in 7 tosses of a fair coin?
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