Best Answer

For n in [1, 16], Prob = nC0*2-n.

For n in [17, 32] Prob = (nC0+nC1)*2-n

For n in [33, 48] Prob = (nC0+nC1+nC2)*2-n

In general,

For n in [(k-1)*16, k*16] Prob = (nC0+nC1+nC2+...+nCk-1)*2-n.

Q: What is the probability that there will be 93.75 percent or more HEADS in n tosses?

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9375% = 9375/100 = 75/8

.9375 set up a ratio: 15/100 = x/6.25 solve for x =.9375

9375/10000

To convert any decimal to percent, simply multiply the decimal by 100. Thus, 0.9375 × 100 = 93.75%

it's 93.75. Simple, 15/16=.9375 multiply it by 100.

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9375% = 9375/100 = 75/8

To change 9375 into a percent you need to do .9375x100 and your percent would be 93.75 . (i hope i helped )

937,500%

.9375 set up a ratio: 15/100 = x/6.25 solve for x =.9375

12500 x 75 % = 9375

0.9375 as a fraction and a percent =9375/10000 or 15/16 in fraction93.75 in percent

9375/10000

To convert any decimal to percent, simply multiply the decimal by 100. Thus, 0.9375 × 100 = 93.75%

It is 9375/1.

it's 93.75. Simple, 15/16=.9375 multiply it by 100.

0.9375 = 9375/10000 = 15/16

3 x 55 = 9375