With a dihybrid cross, there are 9 possible genotypes and 4 possible phenotypes.
The ratio of phenotypes expected is 9 LR : 3 Lr : 3 lR : 1 lr.
The probability of a homozygous dominant for both traits is 1/16 or 6%.
The probability of having a dominant phenotype for both traits is 9/16 or 56%.
9/16 is roughly equal to 3/5 - so this is the expected ratio.
There is no single answer to this question.First, some definitions. PHENOTYPE is how the trait is physically displayed in the person, so the parents in this case have the phenotypes O and A. GENOTYPE is the pair of genes that a person carries that determines their phenotype. A RECESSIVE gene is one "trumped" by a DOMINANT gene in the genotype; for blood typing, O is the recessive gene and A and B are dominant. For a person to show the recessive phenotype, they must carry BOTH recessive genes; so, a person with type O must carry two O genes, genotype "OO".OK, now for our situation. The O parent has genotype OO, as explained above, and so can ONLY pass on the O gene. The type A parent, however, can have genotype AA or AO. Because the A gene is dominant, with the AO genotype the parent is still type A but can pass on EITHER the A gene or the O gene. The child can therefore end up with phenotype AO and be type A or OO and be type O. If exactly one-half of people with type A blood have genotype AA and one-half have AO, the probability of this child being type A is 75%.For the Rh factor (positive and negative), positive is the dominant trait and negative is recessive. The A- parent must be genotype -/- and can only pass on the - gene. The O+ parent can be +/+ or +/- and can pass on either gene, same situation as above. Again, if people with Rh type positive are split exactly 50/50 in genotypes, this child has a 75% chance of being positive.
It depends on the genotype of the childs other parent. If your partner is heterozygous as well then there is a 25% chance your child will be homozygous recessive. If they are homozygous dominant then none of your children will have the phenotype of the recessive trait. They will just possibly be carriers of the recessive allele.
Well, it depends. 90-95% of right handed people are left hemisphere dominant, but 65-75% of LEFT-handed people are LEFT hemisphere dominant.
The answer is b. Bill...somethingThe correct answer would be B. Bill is recessive for height and dominant for hair color.
A person with blood group O is homozygous for the recessive allele: ii.
There are three alleles for blood type which can be represented by IA, IB, and i. A person with blood type O has the genotype ii. A person with blood type AB has genotype IAIB. If these two people produce children, those children will inherit one allele from each parent. They will therefore certainly inherit the i allele from their mother and either the IA or the IB from their father. The children with the genotype IAi will have type A blood, since the IA allele is dominant to the i allele. The children with the genotype IBi will have type B blood, since the IB allele is also dominant to the i allele.
There is no single answer to this question.First, some definitions. PHENOTYPE is how the trait is physically displayed in the person, so the parents in this case have the phenotypes O and A. GENOTYPE is the pair of genes that a person carries that determines their phenotype. A RECESSIVE gene is one "trumped" by a DOMINANT gene in the genotype; for blood typing, O is the recessive gene and A and B are dominant. For a person to show the recessive phenotype, they must carry BOTH recessive genes; so, a person with type O must carry two O genes, genotype "OO".OK, now for our situation. The O parent has genotype OO, as explained above, and so can ONLY pass on the O gene. The type A parent, however, can have genotype AA or AO. Because the A gene is dominant, with the AO genotype the parent is still type A but can pass on EITHER the A gene or the O gene. The child can therefore end up with phenotype AO and be type A or OO and be type O. If exactly one-half of people with type A blood have genotype AA and one-half have AO, the probability of this child being type A is 75%.For the Rh factor (positive and negative), positive is the dominant trait and negative is recessive. The A- parent must be genotype -/- and can only pass on the - gene. The O+ parent can be +/+ or +/- and can pass on either gene, same situation as above. Again, if people with Rh type positive are split exactly 50/50 in genotypes, this child has a 75% chance of being positive.
Albinism is a recessive trait, meaning that an albino person has the genotype AA, while a person who isn't albino has the trait Aa or AA. Two albino people (AA x AA) will have all albino children. Aa x AA will have a 50% probability of albino children, and 50% normal children who are carriers (Aa). AA x AA will have all normal children who are carriers (Aa). Aa x Aa will have 25% AA (normal/non carriers), 25% AA (albino), and 50% Aa (normal/carriers) offspring. AA x AA will have all normal children who are not carriers (AA).*A person who has the genotype Aa is a carrier because they carry the allele (a) for albinism but they are not albino. The allele (A) is dominant so it covers the (a) allele.
The name of the gene pair that consists of a dominant and recessive allele, i.e. (Xx) will be a heterozygous allele. In this situation, the characteristics of the dominant characteristic will mask that of the recessive allele. People have have a heterozygous genotype may be carriers for diseases that reside on the recessive allele.
Many types of dwarfism are dominant so only other little people and they can certainly produce non-dwarf children.
Bit of a judgmental question, like asking which is better black people or white people. It very much depends on the trait. In Cystic fibrosis the homozygous recessive carriers get sick. In Sickle cell anemia its the Homozygous dominant allele that is expressed. Most diseases are usually the recessive type which is lucky, if they were dominant then inherited problems would be far more wide spread than they are today. Genotype is not restricted to disease however as many other factors are also expressed differently depending on the type of allele present. For example the gene for dark hair is dominant over the recessive gene for blond hair, this is why there are so many naturally dark haired people. Hope this helps.
Yes to the first one, no to the second one. Firstly, widow's peak is caused by a dominant gene while a straight hairline is caused by a recessive gene. Let 'H' be dominant and 'h' be recessive. So for a dominant gene, the trait still will be expressed whether the genotype of the person is homozygous dominant(HH) or heterozygous(Hh). For a recessive gene however, the trait will only be expressed when the genotype of the person is homozygous recessive (hh). So two people with a widow's peak CAN have a child with a stright hairline, provided both of their genotypes are Hh. This is because by crossing their genotypes, they can have a possibility of having child with the genotype HH(widow's peak), Hh(widow's peak), and also hh(straight hairline). The ratio of these three possibilities however, are 1:2:1. So the odds of having a child with a straight hairline in this case is 1:3. If the two people who have widow's peak have the genotype HH or one of them HH and the other Hh, then the possibility of having a child with a straight hairline is 0. This is because by crossing their genotypes together, the genotype of the child will either be HH for the first case, and HH or Hh for the second case. For two people who have a straight hairline, the genotype of both will definitely be homozygous recessive (hh), thus child will definitely have the recessive gene. Therefore, it is not possible for two people with straight hairline to have a child with widow's peak.
It depends on the genotype of the childs other parent. If your partner is heterozygous as well then there is a 25% chance your child will be homozygous recessive. If they are homozygous dominant then none of your children will have the phenotype of the recessive trait. They will just possibly be carriers of the recessive allele.
CC
All people are dominant, all people are submissive.
He should be a mix in between just like he is when he is with other people. His job is to guide his children together with his wife.
CC is the phenotype for sickle cell anemia. They can also have SS or SC genotypes. These people can marry only some other genotypes and not have their children develop the disease.