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∙ 12y agoWith a dihybrid cross, there are 9 possible genotypes and 4 possible phenotypes.
The ratio of phenotypes expected is 9 LR : 3 Lr : 3 lR : 1 lr.
The probability of a homozygous dominant for both traits is 1/16 or 6%.
The probability of having a dominant phenotype for both traits is 9/16 or 56%.
9/16 is roughly equal to 3/5 - so this is the expected ratio.
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∙ 12y agoThe probability of a child inheriting a dominant allele for one gene from each parent is 1/4, since each parent has a 1/2 chance of passing on the dominant allele. Therefore, the probability of having 3 out of 5 children fulfilling this condition is given by the binomial distribution formula, which calculates the probability of getting exactly 3 successes out of 5 trials. This probability can be determined using statistical software or calculators and is approximately 30%.
There is no single answer to this question.First, some definitions. PHENOTYPE is how the trait is physically displayed in the person, so the parents in this case have the phenotypes O and A. GENOTYPE is the pair of genes that a person carries that determines their phenotype. A RECESSIVE gene is one "trumped" by a DOMINANT gene in the genotype; for blood typing, O is the recessive gene and A and B are dominant. For a person to show the recessive phenotype, they must carry BOTH recessive genes; so, a person with type O must carry two O genes, genotype "OO".OK, now for our situation. The O parent has genotype OO, as explained above, and so can ONLY pass on the O gene. The type A parent, however, can have genotype AA or AO. Because the A gene is dominant, with the AO genotype the parent is still type A but can pass on EITHER the A gene or the O gene. The child can therefore end up with phenotype AO and be type A or OO and be type O. If exactly one-half of people with type A blood have genotype AA and one-half have AO, the probability of this child being type A is 75%.For the Rh factor (positive and negative), positive is the dominant trait and negative is recessive. The A- parent must be genotype -/- and can only pass on the - gene. The O+ parent can be +/+ or +/- and can pass on either gene, same situation as above. Again, if people with Rh type positive are split exactly 50/50 in genotypes, this child has a 75% chance of being positive.
Yes, individuals who are heterozygous for a recessive allele but have a normal phenotype will not typically pass on the harmful recessive allele to their children unless their partner also carries the recessive allele. This is because the dominant allele masks the presence of the recessive allele.
A recessive allele can seem to disappear when a dominant allele is present. This is because the dominant allele masks the expression of the recessive allele, causing it to not be visibly expressed in the individual's phenotype. However, the recessive allele can still be passed on to offspring and may reappear in future generations.
The statement "They inherited the gene for blue eyes from their parents" most clearly refers to a person's genotype, as it specifically mentions the genetic information passed down from one generation to the next that determines an individual's traits.
A person with type O blood has a genotype of OO. This means they have two recessive O alleles and do not have the A or B blood type antigens on their red blood cells.
There are three alleles for blood type which can be represented by IA, IB, and i. A person with blood type O has the genotype ii. A person with blood type AB has genotype IAIB. If these two people produce children, those children will inherit one allele from each parent. They will therefore certainly inherit the i allele from their mother and either the IA or the IB from their father. The children with the genotype IAi will have type A blood, since the IA allele is dominant to the i allele. The children with the genotype IBi will have type B blood, since the IB allele is also dominant to the i allele.
A man with a genotype of Cc means he has one allele for the dominant trait (C) and one allele for the recessive trait (c). This genotype indicates that he carries both versions of the gene and can pass on either the dominant or recessive trait to his offspring. The expression of the dominant or recessive trait will depend on how the alleles interact with each other.
There is no single answer to this question.First, some definitions. PHENOTYPE is how the trait is physically displayed in the person, so the parents in this case have the phenotypes O and A. GENOTYPE is the pair of genes that a person carries that determines their phenotype. A RECESSIVE gene is one "trumped" by a DOMINANT gene in the genotype; for blood typing, O is the recessive gene and A and B are dominant. For a person to show the recessive phenotype, they must carry BOTH recessive genes; so, a person with type O must carry two O genes, genotype "OO".OK, now for our situation. The O parent has genotype OO, as explained above, and so can ONLY pass on the O gene. The type A parent, however, can have genotype AA or AO. Because the A gene is dominant, with the AO genotype the parent is still type A but can pass on EITHER the A gene or the O gene. The child can therefore end up with phenotype AO and be type A or OO and be type O. If exactly one-half of people with type A blood have genotype AA and one-half have AO, the probability of this child being type A is 75%.For the Rh factor (positive and negative), positive is the dominant trait and negative is recessive. The A- parent must be genotype -/- and can only pass on the - gene. The O+ parent can be +/+ or +/- and can pass on either gene, same situation as above. Again, if people with Rh type positive are split exactly 50/50 in genotypes, this child has a 75% chance of being positive.
The name of the gene pair that consists of a dominant and recessive allele, i.e. (Xx) will be a heterozygous allele. In this situation, the characteristics of the dominant characteristic will mask that of the recessive allele. People have have a heterozygous genotype may be carriers for diseases that reside on the recessive allele.
Many types of dwarfism are dominant so only other little people and they can certainly produce non-dwarf children.
Yes to the first one, no to the second one. Firstly, widow's peak is caused by a dominant gene while a straight hairline is caused by a recessive gene. Let 'H' be dominant and 'h' be recessive. So for a dominant gene, the trait still will be expressed whether the genotype of the person is homozygous dominant(HH) or heterozygous(Hh). For a recessive gene however, the trait will only be expressed when the genotype of the person is homozygous recessive (hh). So two people with a widow's peak CAN have a child with a stright hairline, provided both of their genotypes are Hh. This is because by crossing their genotypes, they can have a possibility of having child with the genotype HH(widow's peak), Hh(widow's peak), and also hh(straight hairline). The ratio of these three possibilities however, are 1:2:1. So the odds of having a child with a straight hairline in this case is 1:3. If the two people who have widow's peak have the genotype HH or one of them HH and the other Hh, then the possibility of having a child with a straight hairline is 0. This is because by crossing their genotypes together, the genotype of the child will either be HH for the first case, and HH or Hh for the second case. For two people who have a straight hairline, the genotype of both will definitely be homozygous recessive (hh), thus child will definitely have the recessive gene. Therefore, it is not possible for two people with straight hairline to have a child with widow's peak.
Homozygous recessive is a genotype, referring to the specific combination of alleles (e.g., rr) at a particular gene locus. This genotype results in a specific phenotype (physical traits) when an individual inherits two copies of the same recessive allele at a particular gene locus.
The word genotypes is in reference to the alleles an individual receives at fertilization. Lets say that the allele/gene/trait, genotype for the Tall plant is T and dominate and the allele/gene/trait genotype for the short plant is t and recessive. If the genotype is an homozygous allele/gene/trait has two dominate alleles/genes/traits seen as two capital letters ex: dominate tall=TT or if the genotype is homozygous with two recessive alleles/genes/traits it will have two lower case letters ex: short=tt. If the genotype is heterozygous is a Tall plant that means the allele/gene/trait will have one dominate T=Tall and one recessive t=short and it will look like this Tt and with this genotype a Tall plant will be produce "T", even though that plant will still carry an allele/gene/trait for shortness "t". Tips: homozygous [Gk.homo means same and zygous means balance] & heterozygous [Gk.hetero means different and zygous means balance]
CC
All people are dominant, all people are submissive.
Yes, individuals who are heterozygous for a recessive allele but have a normal phenotype will not typically pass on the harmful recessive allele to their children unless their partner also carries the recessive allele. This is because the dominant allele masks the presence of the recessive allele.
Albinism is a recessive trait, meaning that an albino person has the genotype AA, while a person who isn't albino has the trait Aa or AA. Two albino people (AA x AA) will have all albino children. Aa x AA will have a 50% probability of albino children, and 50% normal children who are carriers (Aa). AA x AA will have all normal children who are carriers (Aa). Aa x Aa will have 25% AA (normal/non carriers), 25% AA (albino), and 50% Aa (normal/carriers) offspring. AA x AA will have all normal children who are not carriers (AA).*A person who has the genotype Aa is a carrier because they carry the allele (a) for albinism but they are not albino. The allele (A) is dominant so it covers the (a) allele.