When you are asked for the product of something, it means you multiply the numbers. 2 times 3 is 6.
6
1
Find the product of 2 and 5 and then divide 3
24
As a product of its prime factors: 2*2*3*3*5*5 = 900
No. The easiest counter-example to show that the product of two irrational numbers can be a rational number is that the product of √2 and √2 is 2. Likewise, the cube root of 2 is also an irrational number, but the product of 3√2, 3√2 and 3√2 is 2.
The product of 2 and 3 is 6. A product is the answer to a multiplication problem, so 2x3=6.
As a product of its prime factors: 2*2*2*3*3 = 72
As a product of its prime factors: 2*2*2*2*3*3 = 144
As a product of its prime factors: 2*2*3*3 = 36
Find the product of 2 and 5 and then divide 3
As a product of its prime factors: 2*2*2*2*3*3*11 = 1584
24
As a product of its prime factors: 2*2*3*3*7 = 252
120 = 2 * 2 * 2 * 3 * 5 Written as a product of powers is (2^3) * 3 * 5
Product is 18.
420,481,800 as a product of prime factors is: 2 * 2 * 2 * 3 * 3 * 3 * 5 * 5 * 77,867
3+ x/ 2
As a product of its prime factors: 2*2*2*2*3 = 48 As a product of its prime factors: 2*3*3*3 = 54