As a product of its prime factors: 2*2*3*3*5*5 = 900
2x3x4.
No. The easiest counter-example to show that the product of two irrational numbers can be a rational number is that the product of √2 and √2 is 2. Likewise, the cube root of 2 is also an irrational number, but the product of 3√2, 3√2 and 3√2 is 2.
The product of 2 and 3 is 6. A product is the answer to a multiplication problem, so 2x3=6.
The product of a number and its reciprocal is always 1. In this case, the reciprocal of 2/3 is 3/2. When you multiply 2/3 by 3/2, you get (2/3) * (3/2) = 6/6 = 1.
As a product of its prime factors: 2*2*2*3*3 = 72
As a product of its prime factors: 2*2*2*2*3*3 = 144
As a product of its prime factors: 2*2*3*3 = 36
120 = 2 * 2 * 2 * 3 * 5 Written as a product of powers is (2^3) * 3 * 5
As a product of its prime factors: 2*2*3*3*7 = 252
420,481,800 as a product of prime factors is: 2 * 2 * 2 * 3 * 3 * 3 * 5 * 5 * 77,867
Product is 18.
As a product of its prime factors: 2*2*2*2*3 = 48 As a product of its prime factors: 2*3*3*3 = 54
3+ x/ 2
As a product of its prime factors: 2*2*2*2*3 = 48 or as 2^4 times 3 = 48
Rewrite the factors and product. 2*3^2*5 = 3^2*2*5
24 can be expressed as a product of primes as 2^3 * 3^1.