2 times 3 times 5=30 thanks for reading
As a product of its prime factors: 2*2*3*3*5*5 = 900
As a product of its prime factors: 2*2*3*3*5*5*5 = 4500
120 = 2 * 2 * 2 * 3 * 5 Written as a product of powers is (2^3) * 3 * 5
Rewrite the factors and product. 2*3^2*5 = 3^2*2*5
420,481,800 as a product of prime factors is: 2 * 2 * 2 * 3 * 3 * 3 * 5 * 5 * 77,867
2+3 = 5 and 2*3 = 6
It is: 2*2*3*3*5*5*5 = 4500
As a product of its prime factors: 2*2*2*3*5*5*5 = 3000
As a product of its prime factors: 2*3*5*5 = 150 or as 2*3*52 = 150
As a product of its prime factors 2*3*3*3*5*5 = 1350
As a product of its prime factors: 2*2*2*3*3*3*5*5*5 = 27,000
The prime factorization of 150 is 2 * 3 * 5^2. The distinct prime factors are 2, 3, and 5. To find the product of these distinct prime factors, you simply multiply them together: 2 * 3 * 5 = 30. Therefore, the product of the distinct prime factors of 150 is 30.