78 multiplied by 53 is 4,134.
53
53 + 25 = 78
131
B. 53 neutrons. The number of neutrons in an atom is calculated by subtracting the number of protons from the atomic mass of the isotope. Since Iodine-131 has an atomic mass of approximately 131, and it has 53 protons, the number of neutrons is 131 - 53 = 78.
Iodine is element number 53 and and so has 53 protons. There are thus 131-53 = 78 neutrons
78/1.06 = 7800/106 = 3900/53
78 as a product of its prime factors is: 2 x 3 x 13 = 78
537 round to 530 78 round to 80 53*2 = 106 106*2 = 212 121*2 = 424 and the two 0s - one each from 530 and 80 - make it 42400. [The exact answer is 41886]
45 * 78 = 3510
The product of 78 and 7 is 546
78 and 10
1,162 multiplied by 78 is 90,636.