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What is 78 - 25?
53
What is 53 plus 25?
53 + 25 = 78
If an isotope known as iodine 131 has 53 protons How many neutrons does is have A 78 B 53 C 68 or D 184?
B. 53 neutrons. The number of neutrons in an atom is calculated by subtracting the number of protons from the atomic mass of the isotope. Since Iodine-131 has an atomic mass of approximately 131, and it has 53 protons, the number of neutrons is 131 - 53 = 78.
What is 53 plus 78?
131
What is the number of neutrons in atom I131?
Iodine is element number 53 and and so has 53 protons. There are thus 131-53 = 78 neutrons
What is the fractional notation of 78 to 1.06?
78/1.06 = 7800/106 = 3900/53
How do you round 537 and 78 to estimate the product 537 and 78?
537 round to 530 78 round to 80 53*2 = 106 106*2 = 212 121*2 = 424 and the two 0s - one each from 530 and 80 - make it 42400. [The exact answer is 41886]
Express 78 as a product of its prime factors?
78 as a product of its prime factors is: 2 x 3 x 13 = 78
What is the product of 45 and 78?
45 * 78 = 3510
What is 78 x7?
The product of 78 and 7 is 546
What is the product of 78 and 10?
78 and 10
-53 9v plus 1 -26?
the solution to the equation -53 plus 1 -26 is -78.
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