42
7 * 2/3 = 14/3 or 42/3
It is: (2*3)+7 = 13
7)441 7)63 3)9 3)9 3)3 = 1 Hence 441 is the product of 7x7x3x3 = 7^(2) x 3^(2) = (7 x3)^(2) = 21^(2)
As a product of its prime factors: 2*2*3*3*7 = 252
42 as a product of its prime factors is 2*3*7. 90 as a product of its prime factors is 2*3*3*5.
As a product of its prime factors: 2*2*3*3*3*5*7 = 3780
The prime factors are: 2, 3 and 7. (2*3*7 = 42)
The prime factors of 2058 are 2*3*7*7*7, or 2 × 3 × 73.
It is: 2*2*3*3*3*5*7 = 3780
It's easier to see with prime factorizations. Consider 30 and 42. 2 x 3 x 5 = 30 2 x 3 x 7 = 42 Their product is (2 x 3 x 5)(2 x 3 x 7) = 1260 Their GCF is 2 x 3 Their LCM is 2 x 3 x 5 x 7 That product is (2 x 3)(2 x 3 x 5 x 7) = 1260 Consider two prime numbers, 5 and 7. Their product is 35. Their GCF is 1. Their LCM is 35. That product is also 35.
2 x 3 x 3 x 7 = 126 =2*7*3*3
It is: 2*2*3*3*7 = 252 or in exponents 2^2 *3^2 *7 = 252